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SVETLANKA909090 [29]
3 years ago
14

On a coordinate plane, a parabola opens up. It goes through (negative 7.5, 4), has a vertex of (negative 3, negative 9), and goe

s through (1.5 4). Solid circles appear on the parabola at (negative 7, 1.75), (negative 6, negative 3), (negative 3, negative 9), (0, negative 3), (1, 1.75).
Which is f(–3) for the quadratic function graphed?
Mathematics
1 answer:
morpeh [17]3 years ago
7 0

Answer:

f(-3) = -9.

Step-by-step explanation:

The equation of the curve in vertex form is:

f(x) = a(x + 3)^2 - 9     a is positive as the parabola opens up.

It passes through the point (1.5, 4), so

4 = a(1.5 + 3)^2 - 9

20.25a = 13

a = 13/20.25

a = 0.6420.

So the equation of the graph is

0.6420(x + 3)^2 - 9.

f(-3) = 0.6420(-3 + 3)^2 - 9

= 0.642*0 - 9.

= -9.

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