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sleet_krkn [62]
3 years ago
6

Explain determination ?? please follow me gyus ​

Mathematics
1 answer:
icang [17]3 years ago
7 0

Answer:

Determination is a positive emotional feeling that involves persevering towards a difficult goal in spite of obstacles. Determination occurs prior to goal attainment and serves to motivate behavior that will help achieve one's goal.

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Need help answering this algebra nation question!
My name is Ann [436]

Answer:

Option 1, 2 and 4

Step-by-step explanation:

3x-4y-8= 12

3x-4y= 12+8 (bring constants to 1 side)

3x-4y= 20 (simplify)

For a point to be a solution of the above equation, substitute the x and y coordinates into 3x-4y and see if it equals to 20.

Option 1: (0, -5)

3(0)-4(-5)= 20

This is correct

2) (4, -2)

3(4)-4(-2)=20

This is correct

3) (8,2)

3(8)-4(2)= 16

This is incorrect.

4) (-16, -17)

3(-16)-4(-17)= 20

This is correct.

5) (-1, -8)

3(-1)-4(-8)= 29

This is incorrect.

6) (-40, -34)

3(-40)-4(-34)= 16

This is incorrect.

3 0
3 years ago
After reading 7/9 of a book, 40 pages are left. Find the total number of pages in the book​
dimaraw [331]

Answer:

180 pages

Step-by-step explanation:

let x be the number of pages in the book , then

\frac{7}{9} x + 40 = x ( multiply through by 9 to clear the fraction )

7x + 360 = 9x ( subtract 7x from both sides )

360 = 2x ( divide both sides by 2 )

180 = x

The total number of pages in the book is 180

6 0
3 years ago
The average annual cost of the first year of owning and caring for a large dog is $1,843 (US News and World Report, September 9,
ICE Princess25 [194]

Answer:

a. Error is 0.14

b. between 1913.68 to 1772.32

Step-by-step explanation:

Requirement a)

The margin of error is a statistic expressing the amount of random sampling error in a survey's results.

Given,

Size of the sample n = 50

We know, At 95% confidence interval,

The margin of error,

= 0.98/√n  

= 0.98/√50

= 0.98/7.07

= 0.13859 ~ 0.14

So the margin of error at 95% confidence level is 0.14.

Requirement b)

Given,

Standard deviation σ = 255

Population mean z = 1814

Size of the sample n = 50

We know, At 95% confidence interval,

(z-µ)/(σ/√n)  < Z_0.05

= - Z_0.05 < (z-µ)/(σ/√n) < Z_0.05

= - 1.96 * σ/√n < (z-µ)/(σ/√n)*  σ/√n  < 1.96 * σ/√n  [ in two tail Z test the value of Z_0.05 is 1.96 ]

= - 1.96 * 255/√50 < Z-µ <  1.96 * 255/√50

= -70.6828 < Z-µ < 70.6828

= 70.6828 > µ - Z > -70.6828

= 70.6828 + Z > µ > -70.6828 + Z

= 70.6828 + 1814 > µ > -70.6828 + 1814

=1913.68 > µ > 1772.32

So, the sample mean would be between 1913.68 to 1772.32.

7 0
3 years ago
All the names that apply to the number -1.5
Blababa [14]
-3/2 -15/10 this is called a negative number. Negative 1 and 5 tenths
8 0
3 years ago
What’s the answer to this? by the way you have to estimate
Furkat [3]

the answer is 2 if you estimate to the tenths place

7 0
2 years ago
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