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Aleks04 [339]
3 years ago
6

What is the equation in standard form of the line which passes through (–2, –3) and has a slope of ? (5 points)

Mathematics
1 answer:
nevsk [136]3 years ago
3 0
It should be y=-?x-3
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How many 6 oz servings are in a 1.125-quart pitcher of lemonade? There are servings. Enter an integer or decimal number[more..]
suter [353]

Answer:

6

Step-by-step explanation:

1 qt = 4 cups

1 cup = 8 fl oz

1.125 qt * (4 cups)/(1 qt) * (8 fl oz)/(1 cup) = 36 fl oz

(36 fl oz)/(6 fl oz) = 6

Answer: 6 servings

5 0
3 years ago
Solve 34*17 using an area model
Monica [59]
Well put 34 units on the left vertically and 17 units on the bottom hoizontially... fill it up and count how many you have
3 0
3 years ago
Read 2 more answers
Please help.<br> Algebra.
Talja [164]

Answer:

y=4

Step-by-step explanation:

7 0
2 years ago
Please help me with this question??m
Keith_Richards [23]

Answer:

75

Step-by-step explanation:

f(1) = 7

f(n) = 3f(n-1) + 3

So what you are trying to do here is find the recursive value (that's what it is called) for f(n). Computers love this sort of thing, but we humans have to do it slowly and carefully.

So let's try f(2)

That means that f(2) = 3*f(n-1) + 3

but if f(2) is used it means that you have to know f(2-1) which is just f(1) and we know that.

so f(2) = 3*f(1)+3

f(2) = 3*7 + 3

f(2) = 21 + 3

f(2) = 24

Now do it again. We now know F(2), so we should be able to find f(3)

f(3) = 3*f(3 - 1) + 3  

f(3) = 3*f(2) + 3      We know that f(2) = 24

f(3) = 3* 24 + 3

f(3) = 72 + 3

f(3) = 75

7 0
2 years ago
A rectangular metal plate is measured to be 7.6cm long and 3.1cm wide, both correct to one decimal place.
ElenaW [278]

Answer:

We know that the rectangular plate has measures of:

length = 7.6 ± 0.05 cm

width = 3.1 ± 0.05 cm

(the error is 0.05cm because we know that both measures are correct to one decimal place)

First, the upper bound of the length is equal to the measure of the length plus the error, this is:

L = 7.6 cm + 0.05 cm = 7.65 cm

The upper bound of the area is the area calculated when we use the upper bound of the length and the upper bound of the widht.

Remember that the area for a rectangle of length L and width W, is:

A = W*L

Then the upper bound of the area is:

A = (7.6cm + 0.05cm)*(3.1cm + 0.05cm) = 10.8 cm^2

5 0
3 years ago
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