nine days ago the area covered by a mold on a piece of bread was 3 square inches today the mold covers 9,square inches find the
2 answers:
The rate of change of the area covered by a mold on a piece of bread is
Further explanation:
The rate of change can be expressed as follows,
Given:
Nine days ago the area covered by a mold on a piece of bread was 3 square inches.
Today the mold covers 9 square inches.
Explanation:
The final area covered by a mold on a piece of bread is
The initial area covered by a mold on a piece of bread is
Initial time is 0.
Final time is 9.
The rate of change can be calculated as follows,
The rate of change of the area covered by a mold on a piece of bread is
Learn more:
1. Learn more about inverse of the functionhttps://brainly.com/question/1632445.
2. Learn more about equation of circle brainly.com/question/1506955.
3. Learn more about range and domain of the function brainly.com/question/3412497
Answer details:
Grade: High School
Subject: Mathematics
Chapter: Number system
Keywords: Area, covered area, mold, piece, bread, 3 square inches, today, mold covers, rate of change, nine days ago, 9 square inches, final value, initial value, mold.
You might be interested in
Answer:
The values of given expressions are:
1. gh = -21
2. g^2 - h = 46
3. g + h^2 = 2
4. g + h = -4
5. h - g = 10
6. g - h = -10
Step-by-step explanation:
Given values of g and h are:
g = -7
h = 3
<u>1. gh</u>
The two numbers are being multiplied
Putting the values
<u>2. g^2-h</u>
Putting the values
<u>3. g+h^2</u>
Putting the values
<u>4. g+h</u>
Putting the values
<u>5. h-g</u>
Putting the values
<u>6. g-h</u>
Putting values
Hence,
The values of given expressions are:
1. gh = -21
2. g^2 - h = 46
3. g + h^2 = 2
4. g + h = -4
5. h - g = 10
6. g - h = -10