HELP ASAP WILL MARK BRAINIEST!!!!!

C) Write another name for 25. -

EastWind [94]

Answer:

Twenty five

Step-by-step explanation:

8 0

3 years ago

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Assuming all other requirements are met, which of the following taxpayers do NOT qualify for the 2021 Earned Income Tax Credit?

Ilia_Sergeevich [38]

Based on the information given, the person who doesn't qualify for the income tax credit will be A. Ivy, age 22, is single with no dependents. She is not a dependent of another person. She has wages of $6,500 and an investment income of $11,150.

It should be noted that the earned income tax credit is important as it helps low-income workers get a tax break.

From the options given, Ivy is the taxpayer that does not qualify for the 2021 Earned Income Tax Credit. This is because she's not a dependent of another person.

Learn more about tax credit on:

brainly.com/question/25895721

8 0

2 years ago

A discount store takes 50% off of the retail price of a desk. For the store's holiday sale, it takes an additional 20% off of al

Serhud [2]

We are given the retail price of desk as $320. The store takes 50% off of the retail price of desk, then its price would become half of the original.

So its new price would be $160.

Now it says that it takes an additional 20% off of all furniture on store's holiday sale. So we need to cut off 20% from new price $160.

Holiday discount = 20% of $160 = 0.2 × 160 = 32.

Final selling price would be = $160 - $32 = $128.

So $128 is the final answer.

3 0

3 years ago

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Question 1 2XY3 + 3XY3 5X2Y6 True or False

Law Incorporation [45]

U believe it’s F....

5 0

3 years ago

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A sample of 81 account balances of a credit company showed an average balance of $1,200 with a standard deviation of $126.

TEA [102]

Answer:

(a) Null Hypothesis, $H_0$ : $\mu$ = $1,150

Alternate Hypothesis, $H_A$ : $\mu$ $\neq$ $1,150

(b) The test statistic is 3.571.

(c) We conclude that the mean of all account balances is significantly different from $1,150.

Step-by-step explanation:

We are given that a sample of 81 account balances of a credit company showed an average balance of $1,200 with a standard deviation of $126.

We have test the hypothesis to determine whether the mean of all account balances is significantly different from $1,150.

Let $\mu$ = mean of all account balances

(a)So, Null Hypothesis, $H_0$ : $\mu$ = $1,150 {means that the mean of all account balances is equal to $1,150}

Alternate Hypothesis, $H_A$ : $\mu$ $\neq$ $1,150 {means that the mean of all account balances is significantly different from $1,150}

The test statistics that will be used here is One-sample t test statistics as we don't know about population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample average balance = $1,200

s = sample standard deviation = $126

n = sample of account balances = 81

(b) So, test statistics = $\frac{1,200-1,150}{\frac{126}{\sqrt{81} } }$ ~ $t_8_0$

= 3.571

The value of the sample test statistics is 3.571.

(c) Now, P-value of the test statistics is given by the following formula;

P-value = P( $t_8_0$ > 3.571) = Less than 0.05%

Because in the t table the highest critical value for t at 80 degree of freedom is given between 3.460 and 3.373 at 0.05% level.

Now, since P-value is less than the level of significance as 5% > 0.05%, so we sufficient evidence to reject our null hypothesis.

Therefore, we conclude that the mean of all account balances is significantly different from $1,150.

8 0

4 years ago