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svetlana [45]
3 years ago
10

You are putting money into a bank account. You start with $100 and add $12 every month. The total amount of money in your accoun

t can be represented by the following equation. (where T is total amount and M is the number of months):
T = 100 + 12 M

If you have $208, how many months have passed?

Show the equation and how you got the answer.
Mathematics
2 answers:
frez [133]3 years ago
8 0

Answer:

9 months

Step-by-step explanation:

Mumz [18]3 years ago
7 0

Answer:

it will be 9 months like the first person said

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-7 + 2x = -45<br> a 1<br> b -19<br> c 11<br> d -16
Marina86 [1]

Answer:

B) -19

Step-by-step explanation:

-7 + 2x = -45

+7             +7

2x = -38

/2      /2

x = -19

7 0
3 years ago
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According to the website www.costofwedding, the average cost of flowers for a wedding is $698. Recently, in a random sample of 4
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Answer:

D) II and III are both correct.

Step-by-step explanation:

The Probability distribution is the function which describes the likelihood of possible values assuming a random variable. The cost of flowers for a wedding is $698. The 95% of all samples of size is 40 and the confidence interval will be mean cost of flowers at wedding. There is confidence that mean cost of wedding flowers is between $701 to $767.

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3 years ago
Ann's first option is a plot of land adjacent to a current park.
oksian1 [2.3K]

Given:

The equation for the area of the first option is:

x^2+200x=166400

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To find:

The side length of the current square park.

Solution:

We have,

x^2+200x=166400

It can be written as:

x^2+200x-166400=0

Splitting the middle term, we get

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x(x+520)-320(x+520)=0

(x-320)(x+520)=0

x=320,-520

We know that the side length of a park cannot be negative. So, the only possible value of x is 320.

Therefore, the most direct method to solve the given equation is splitting the middle term and the side length of the current square park is 320 meters.

4 0
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andreev551 [17]
3/4×2/3=1/2 that is the answer

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P=$24038.60 has to be invested to have $45000 after 19 years
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