The hyperbolic cos (cosh) is given by
cosh (x) = (e^x + e^-x) / 2
The slope of a tangent line to a function at a point is given by the derivative of that function at that point.
d/dx [cosh(x)] = d/dx[(e^x + e^-x) / 2] = (e^x - e^-x) / 2 = sinh(x)
Given that the slope is 2, thus
sinh(x) = 2
x = sinh^-1 (2) = 1.444
Therefore, the curve of y = cosh(x) has a slope of 2 at point x = 1.44
Answer:
Step-by-step explanation:
13.6
I believe it’s 6
Hope this helps you :))
Answer:
The length of the four pieces of protective strip is 96 feet
Step-by-step explanation:
Let the w be the width of the rectangular house and L is length. Since L = w + 16, its perimeter P = 2(w + L)
= 2(w + w + 16)
= 2(2w + 16)
Since the perimeter of the house P = 136 feet,
136 = 2(2w + 16)
dividing through by 2, we have
136/2 = (2w + 16)
68 = (2w + 16)
collecting like terms, we have
68 - 16 = 2w
52 = 2w
dividing through by 2, we have
w = 52/2
w = 26 feet.
Now, since the side walk is 3 foot wide all around, the width of the house plus sidewalk = w + 3 and the length of the house plus sidewalk = L + 3 = w + 16 + 3 = w + 19.
So, the perimeter of the house plus sidewalk which is the perimeter of the four pieces of protective strip is P' = 2(w + 3 + w + 19)
= 2(w + 22)
= 2(26 + 22)
= 2(48)
= 96 feet
So, the length of the four pieces of protective strip is 96 feet.
Answer:
69.75 square inches
Step-by-step explanation:
Add the top and bottom lengths then divide by 2 before multiplying it with the height
1/2x(3+12.5)=7.75
7.75x9=69.75
