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PilotLPTM [1.2K]

3 years ago

13

The slope of a line is –4 and its y-intercept is (0, 4). What is the equation of the line that is perpendicular to the first lin

e and passes through (–8, 2)

1 answer:

Ludmilka [50]3 years ago

3 0

Y=1/4x+4 will be the line

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Which expression represents the distance between the points (11, 4) and (5,8)?

antiseptic1488 [7]

Answer:

$\displaystyle d = 2\sqrt{13}$

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right<u> </u>

<u>Algebra I</u>

Coordinates (x, y)

<u>Algebra II</u>

Distance Formula: $\displaystyle d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Step-by-step explanation:

<u>Step 1: Define</u>

Point (11, 4) → x₁ = 11, y₁ = 4

Point (5, 8) → x₂ = 5, y₂ = 8

<u>Step 2: Find distance </u><em><u>d</u></em>

Simply plug in the 2 coordinates into the distance formula to find distance <em>d</em>

Substitute in points [Distance Formula]: $\displaystyle d = \sqrt{(5-11)^2+(8-4)^2}$
[√Radical] (Parenthesis) Subtract: $\displaystyle d = \sqrt{(-6)^2+(4)^2}$
[√Radical] Evaluate exponents: $\displaystyle d = \sqrt{36+16}$
[√Radical] Add: $\displaystyle d = \sqrt{52}$
[√Radical] Simplify: $\displaystyle d = 2\sqrt{13}$

4 0

3 years ago

In Exercise,find the horizontal asymptote of the graph of the function.<br> f(x) = 8x^3+2/2x^3+x

KIM [24]

Answer:

Horizontal asymptote of the graph of the function f(x) = (8x^3+2)/(2x^3+x) is at y=4

Step-by-step explanation:

I attached the graph of the function.

Graphically, it can be seen that the horizontal asymptote of the graph of the function is at y=4. There is also a <em>vertical </em>asymptote at x=0

When denominator's degree (3) is the same as the nominator's degree (3) then the horizontal asymptote is at (numerator's leading coefficient (8) divided by denominator's lading coefficient (2)) $y=\frac{8}{2}=4$

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3 years ago

In the middle of a test <br> Please answer!

vaieri [72.5K]

Answer:

umm... there is no problem

4 0

3 years ago

Choose 3 values that would make this inequality true. <img src="https://tex.z-dn.net/?f=4%2Bg%20%5Cgeq%209" id="TexFormula1" tit

Elena-2011 [213]

G>=5, so anything above or equal to 5 would count. So, you could use 5, 6, 7.

7 0

3 years ago

64x^2-81 what’s the answer ?

pychu [463]

Answer:

(8x-9)(8x+9)

Step-by-step explanation:

64x^2 - 81

Rewriting

(8x)^2 - 9^2

We recognize that this is the difference of squares

a^2 - b^2 = (a-b)(a+b)

(8x-9)(8x+9)

3 0

3 years ago

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