Answer:
This is because even when the quality of the variable x is 0, the value of b still exists and is the starting point for y.
Step-by-step explanation:
To prove this, we start with the base form of the equation and input 0 for x.
y = mx + b
y = m(0) + b
y = 0 + b
y = b
In this instance the distance will be the hypotenuse of a right angle triangle.
x = 300/sin30 = 600
They are 600 ft away from each other
Answer:
The answer is B
Step-by-step explanation:
Using the vertex of a quadratic function, it is found that:
a) The revenue is maximized with 336 units.
b) The maximum revenue is of $56,448.
<h3>What is the vertex of a quadratic equation?</h3>
A quadratic equation is modeled by:

The vertex is given by:

In which:
Considering the coefficient a, we have that:
- If a < 0, the vertex is a maximum point.
- If a > 0, the vertex is a minimum point.
The demand function is given by:
p(x) = 336 - 0.5x.
Hence, the revenue function is:
R(x) = xp(x)
R(x) = -0.5x² + 336x.
Which has coefficients a = -0.5, b = 336.
Hence, the value of x that maximizes the revenue, and the maximum revenue, are given, respectively, as follows:
More can be learned about the vertex of a quadratic function at brainly.com/question/24737967
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Answer:
Step-by-step explanation:
Corresponding parts of congruent triangles are congruent.
So, XY = AB
3a - 3.9 = 1.7a - 1.3
3a = 1.7a - 1.3 + 3.9
3a = 1.7a + 2.6
3a -1.7a = 2.6
1.3a = 2.6
a = 2.6/1.3
a = 2
ΔABC ≅ ΔXYZ
First two letter
AB = XY
Second and third letters
BC = YZ
Third and first letter
CA = ZX