Any triangle with one angle equal to 90⁰ produces a Pythagoras triangle and the Pythagoras equation can be applied in the triangle.
<h3>What is the Pythagoras Theorem?</h3>
The Pythagoras theorem states that if a triangle is right-angled (90 degrees), then the square of the hypotenuse is equal to the sum of the squares of the other two sides.
In △ABD and △ACB,
∠A = ∠A (common)
∠ADB = ∠ABC (both are right angles)
Thus, △ABD ∼ △ACB (by AA similarity criterion)
Similarly, we can prove △BCD ∼ △ACB.
Thus △ABD ∼ △ACB,
Therefore, AD/AB = AB/AC.
We can say that AD × AC = AB².
Similarly, △BCD ∼ △ACB.
Therefore,
CD/BC = BC/AC.
We can also say that
CD × AC = BC².
Adding these 2 equations, we get
AB² + BC² = (AD × AC) + (CD × AC)
AB² + BC² =AC(AD +DC)
AB² + BC² = AC²
Hence proved
Thus, any triangle with one angle equal to 90⁰ produces a Pythagoras triangle and the Pythagoras equation can be applied in the triangle.
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Answer:
(m + 3) (m - 6)
Step-by-step explanation:
Simplify the following:
m^2 - 3 m - 18
The factors of -18 that sum to -3 are 3 and -6. So, m^2 - 3 m - 18 = (m + 3) (m - 6):
Answer: |
| (m + 3) (m - 6)
Answer:44
Step-by-step explanation:
Answer:
You are correct
Step-by-step explanation:
Start with 1 1/2. This can be made into an improper fraction which is 3/2
Now multiply both top and bottom of 3/2 by 5
(3*5)/(2 * 5) = 15 / 10
16/10 is just slightly bigger than 15/10
