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Ne4ueva [31]
3 years ago
13

A client is asking for a printing solution that will print three sheets of paper with identical information on each page with a

single pass of the printer. Furthermore, the client requests that the solution take the least amount of time and effort to maintain. Which of the following printer types should be recommended?
Computers and Technology
1 answer:
Sergeu [11.5K]3 years ago
7 0

According to the requirements of the client, the printing solution should print three sheets of paper with identical information on each page with a single pass of the printer.

<u>Explanation:</u>

Furthermore, the client requests that it should take the least amount of time and effort to maintain. The printer type according to the requirements should be an impact printer.

Impact printers suit the needs of the client and are easy to maintain due to the low cost. Also, they print by making physical contact with the paper and have a significant speed of printing.

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If(moreDate == true)
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Write a Python program that translates a binary number of n bits to a decimal number. Your program should first ask the user the
KonstantinChe [14]

Answer:

Follows are the code to this question:

n= int(input("please enter number of bits, which want to convert for binary to decimal numbers: "))

p= 1#defining variable p for calculate power

d= 0#defining variable d for calculate decimal value

for i in range(n):#defining for loop for input bits value

   b= int(input("Enter the bit value from lowest to highest: "))#input value in b

   if b==1:#defining if block that check input is 1 value

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   p=p* 2#calculating power

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Output:

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Explanation:

In the above-given code, n variable is defined, which takes the number of bits value which you want to convert into a decimal value.

In the next step, "d and p" variable is defined that calculates the power and decimal number and store its value respectively, in this step, a for loop is used that uses the "b" variable for inputs bits value into lowest to the highest form, and use the if block.

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