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tino4ka555 [31]

3 years ago

10

Use the function f(x) = 2x3 - 3x2 + 7 to complete the exercises.

1 answer:

zavuch27 [327]3 years ago

3 0

Answer:

what are the excersises

Step-by-step explanation:

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Help me solve this pls

kirill [66]

I think the answer is b

8 0

2 years ago

Complete the number patterns <br><br> 1. 1,3,6,10,15,21,__,__<br><br> 2. 1,3,7,13,21, __,__

sweet-ann [11.9K]

23,26...................

5 0

3 years ago

Read 2 more answers

In the supply-and-demand schedule shown above, the equilibrium price for portable music players is _____.

ad-work [718]

$150 because the supply number is equivalent to the demand number

6 0

3 years ago

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What type of system is the following set of equations?

iVinArrow [24]

$-3x+y=-2 \\
y-4=-6x \ \ \ |\times (-1) \\ \\
-3x+y=-2 \\
\underline{-y+4=6x} \\
-3x+y-y+4=6x-2 \\
-3x+4=6x-2 \\
-3x-6x=-2-4 \\
-9x=-6 \\
x=\frac{-6}{-9} \\
x=\frac{2}{3} \\ \\
y-4=-6 \times \frac{2}{3} \\
y-4=-4 \\
y=-4+4 \\
y=0 \\ \\
(x,y)=(\frac{2}{3},0)$

The system has one solution so it's A. consistent and independent.

7 0

2 years ago

Suppose r(t)=costi+sintj+3tk represents the position of a particle on a helix, where z is the height of the particle above the g

Ilia_Sergeevich [38]

a. The $\vec k$ component tells you the particle's height:

$3t=16\implies t=\dfrac{16}3$

b. The particle's velocity is obtained by differentiating its position function:

$\vec v(t)=\dfrac{\mathrm d\vec r(t)}{\mathrm dt}=-\sin t\,\vec\imath+\cos t\,\vec\jmath+3\,\vec k$

so that its velocity at time $t=\frac{16}3$ is

$\vec v\left(\dfrac{16}3\right)=-\sin\dfrac{16}3\,\vec\imath+\cos\dfrac{16}3\,\vec\jmath+3\,\vec k$

c. The tangent to $\vec r(t)$ at $t=\frac{16}3$ is

$\vec T(t)=\vec r\left(\dfrac{16}3\right)+\vec v\left(\dfrac{16}3\right)t$

4 0

2 years ago