What is the distance between (5,2) and (1,-3) on a coordinate plane?
2 answers:
I believe it would be (4,5)
The formula for distance between two points is
d = √ (x2-x1)^2 + (y2-y1)^2
If we apply in given points we get
d = √ (1-5)^2 + (-3-2)^2 = √ (-4)^2 + (-5)^2 = √ 16+25 = √41
d=√41
Good luck!!!
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