Answer:the cost of one day lily = $9 and cost of one pot of ivy = $2
Step-by-step explanation:
Step 1
let day lilies be rep as d
and ivy be represented as i
So that The expression for what Willie spent on 12 day lilies and 4 pots of ivy = $116 be
12 d+ 4i = 116 ---- equation 1
and for Anjali spending $60 on 6 day lilies and 3 pots of ivy be
6d+ 3i = $60------ equation 2
Step 2 --- Solving
12 d+ 4i = 116 ---- equation 1
6d+ 3i = $60------ equation 2
Multiply equation 2 by (2) and subtracting equation 1 from it
12d+ 6i= 120
--12 d+ 4i = 116
2 i= 4
i = 4/2 = 2
TO find d, putting the value of i = 2 in equation 1 and solving
12d+ 4(2) = 116
12d= 116-8
12d= 108
d= 108/12= 9
Therefore the cost of one day lily = $9 and cost of one pot of ivy = $2
Hello!
You want a choice where everyone has an equal chance to answer
The answer is D) All students in each grade because A is biased because students won't be able to answer, B is biased because it is limited to only to football team and C doesn't give girls the chance to answer
The answer is D) All students in each grade
Hope this helps!
Answer:
Step-by-step explanation:
Given that you have eight cards. Five are green and three are yellow. The five green cards are numbered 1, 2, 3, 4, and 5. The three yellow cards are numbered 1, 2, and 3. The cards are well shuffled. You randomly draw one card.
G = card drawn is green
Y = card drawn is yellow
E = card drawn is even-numbered
List:
Sample space = {G1, G2, G3, G4, G5, Y1, Y2, Y3}
2) P(G) = 5/8
3) P(G/E) = P(GE)/P(E)
GE = {G2, G4}
Hence P(G/E) = 2/5
4) GE = {G2, G4}
P(GE) = 2/8 = 1/4
5) P(G or E) = P(G)+P(E)-P(GE)
= 5/8 + 3/8-2/8 = 3/5
6) No there is common element as G2 and G4
Cannot be mutually exclusive
14= 7+7
16= 8+8
18= 9+9
20= 9+11
22= 10+12
24= 12+12
26= 7+8+11
Answer:
C = 2πr = 16.3
2(3.14)r = 16.3
r = 16.3/6.28
r = 2.5955414
Area: A = πr2
A = 3.14(2.5955414)2
A = 21.15366242 
Step-by-step explanation:
The answer would be 21.2
