Answer:
c
Step-by-step explanation:
because that would be the wrong one
In order to understand if the inequalities are always, never or sometimes true, you need to perform the calculations:
A) <span>9(x+2) > 9(x-3)
9x + 18 > 9x - 27
the two 9x cancel out and you get:
+18 > -27
which is always true.
B) <span>6x-13 < 6(x-2)
6x - 13 < 6x - 12</span>
</span><span>the two 6x cancel out and you get:
- 13 < -12
which is always true
C) </span><span>-6(2x-10) + 12x ≤ 180
-12x +60 +12x </span>≤ 180
-12x and +<span>12x cancel out and you get:
60 </span><span>≤ 180
which is always true.
All three cases are always true.</span>
Answer:
its b because the answer for y needs to change in order for the x column to be true
Answer:
g(0.9) ≈ -2.6
g(1.1) ≈ 0.6
For 1.1 the estimation is a bit too high and for 0.9 it is too low.
Step-by-step explanation:
For values of x near 1 we can estimate g(x) with t(x) = g'(1) (x-1) + g(1). Note that g'(1) = 1²+15 = 16, and for values near one g'(x) is increasing because x² is increasing for positive values. This means that the tangent line t(x) will be above the graph of g, and the estimates we will make are a bit too big for values at the right of 1, like 1.1, and they will be too low for values at the left like 0.9.
For 0.9, we estimate
g(0.9) ≈ 16* (-0.1) -1 = -2.6
g(1.1) ≈ 16* 0.1 -1 = 0.6
