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3 years ago

Joan earns $9.25 per hour. She worked 37.6 hours last week. What was the amount of her check?

Mathematics

2 answers:

Vika [28.1K]3 years ago

6 0

37.6*9.25=$<span>347.8 is the right answer</span>

slava [35]3 years ago

3 0

37.6*9.25=$<span>347.8 without deductions</span>

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1.How many combinations are possible from the letters HOLIDAY if the letters are taken?

Lesechka [4]

Using the combination formula, it is found that:

1. A. 7 combinations are possible.

B. 21 combinations are possible.

C. 1 combination is possible.

2. There are 245 ways to group them.

<h3>What is the combination formula?</h3>

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by:

$C_{n,x} = \frac{n!}{x!(n-x)!}$

Exercise 1, item a:

One letter from a set of 7, hence:

$C_{7,1} = \frac{7!}{1!6!} = 7$

7 combinations are possible.

Item b:

Two letters from a set of 7, hence:

$C_{7,2} = \frac{7!}{2!5!} = 21$

21 combinations are possible.

Item c:

7 letters from a set of 7, hence:

$C_{7,7} = \frac{7!}{0!7!} = 1$

1 combination is possible.

Question 2:

Three singers are taken from a set of 7, and four dances from a set of 10, hence:

$T = C_{7,3}C_{10,4} = \frac{7!}{3!4!} \times \frac{10!}{4!6!} = 245$

There are 245 ways to group them.

More can be learned about the combination formula at brainly.com/question/25821700

6 0

2 years ago

1)How many ways can the letters in the word BOOKKEEPER be arranged? (Must show set-up )

sergeinik [125]

Question 1

There are 5 letters (B, O, K, E, R) and there is a total of 10 letters to make up the word.
There are $\frac{10!}{(10-6)!6!}$ ways of arranging the letters, which equal to 210 ways

Question 2

There are seven swimmers in total.
There are $\frac{7!}{(7-1)!1!}$ ways of choosing the first winner, which is 7 ways
There are $\frac{6!}{(6-1)!1!}$ ways of choosing the second winner, which is 6 ways
There are $\frac{5!}{(5-1)!1!}$ ways of choosing the third winner, which is 5 ways
There are 7×6×5=210 ways of choosing first, second, and third winner

Question 3

The probability of eating an orange and a red candy is $\frac{15}{31}$ × $\frac{9}{30}$ , which equals to $\frac{9}{62}$

The probability of eating two green candies is $\frac{7}{31}$ × $\frac{6}{30}$ which equals to $\frac{7}{155}$

3 0

3 years ago

A discount bookstore sells hardcover books for $12 and paperback books for $6. The number of hardcover books, x, sold one day wa

Thepotemich [5.8K]

Answer: the system of equations that represents this situation are

12x + 6y = 180

x = 2y

Step-by-step explanation:

Let x represent the number of hardcover books that were sold in a day.

Let y represent the number of paperback books that were sold in a day.

The discount bookstore sells hardcover books for $12 and paperback books for $6. The total sales that day were $180. It means that

12x + 6y = 180

The number of hardcover books sold that day was twice the number of paperback books. It means that

x = 2y

8 0

3 years ago

What is 97,000 in scientific notation?

lianna [129]

Answer:

9.7 * 10 to power of 4

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

I need help with all 4 of these . And I do need to show work for all of them

malfutka [58]

Answer:

Step-by-step explanation:

11) Profit = Selling price - purchase price - other expenses

$= (2000*7)-12780-26=1194$

12) Profit = Selling price - purchase price - other expenses

$=52.25(550)-28275-32=430.50=430$ (after rounding off)

13) Annual interest on bond

=INterest rate on face value of bond for 1 year

$=2000(6%)=120$

14)Cost of bond

= quoted value (rate)

=3500(80.5)

=2817.50

15) Cost of bond

= quoted value (rate)

=4250(83.5)

=3548.75

3 0

3 years ago