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Doss [256]
4 years ago
12

A polling company has decided to increase the size of its random sample of voters from about 1,000 people to about 2,800 people

right before an election. A poll was designed to estimate the proportion of voters who favor a new law banning cell phone use in internet coffee shops. What is the effect of this increase?
A. To reduce the variability of the estimate
B. To increase the variability to the estimate
C. To reduce the bias of the estimate
D. To increase the bias of the estimate
E. This increase will have no effect because the population size is the same
Mathematics
2 answers:
Damm [24]4 years ago
6 0

Answer:

A. To reduce the variability of the estimate

Step-by-step explanation:

The larger the sample, the less variability there is.

The smaller the sample, the more variability there is.

Bias has to do with how randomly the sample is selected.  Assuming that method doesn't change, the bias doesn't change.

babunello [35]4 years ago
3 0
That there is more people there then people working
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3 years ago
A pair of shoes is on sale for 15% off. With this discount, customers will save $9 if they buy the shoes .In this situation, wha
kozerog [31]

Answer:

$9 is the part, 15% is the percent, and $60 is the whole.

Step-by-step explanation:

$9 is %15 of the whole. This means $9 is the part, 15% is the percent, and the whole is the total cost of the shoes after the discount. The total cost of the shoes after the discount is 60.

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3 years ago
Complete the following sentences to make true statements.
lora16 [44]

Step-by-step explanation:

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6 0
3 years ago
Which equation has solutions of 6 and -6? x2 – 12x + 36 = 0 x2 + 12x – 36 = 0 x2 + 36 = 0 x2 – 36 = 0
Svetlanka [38]

<u>Answer:</u>

The equation that has solutions 6 and -6 is x^2 - 36 = 0

<u>Solution:</u>

We have to find which equation has the solutions 6 and -6.

We have been given three equations.

x^{2}-12 x+36=0  --- eqn 1

x^{2}+12 x-36=0 -- eqn 2

x^{2}-36=0  ---- eqn 3

The 6 and -6 to satisfy any of these equations they have to be the roots of the equation.

This means that when we substitute 6 and -6 in any of the equations and then solve them the answer on simplification should be 0.

This condition should individually be satisfied by both 6 and -6 for any one of the equations.

Now let us try and substitute 6 and -6 in eq1.

Now, substituting 6 in eq1.

62-12×6+36=0

Now we simply the equation to check is the LHS is equal to the RHS of the equation.  

LHS:

72-72=0

RHS:  0  

Since LHS=RHS it is the root of the equation.

Now we check if -6 satisfies eq1.

-62-12×-6+36=0

LHS:

72+72=144

RHS:  0

Hence LHS is not equal to RHS, -6 is not the root of eq1.

Similarly we check for eq2  

Checking for 6 and -6 we get

LHS is not equal to RHS hence this does not satisfy eq2.

Now in the same way we check for eq3

LHS=RHS for both 6 and -6 hence they are the solutions for eq3.

Hence the equation that has solutions 6 and -6 is x^2 - 36 = 0

3 0
3 years ago
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