Question

Factorization of x3+8

Answer 1

I hope this helps you



x^3+2^3



(x+2)(x^2-2x+4)

Answer 2

Answer:

The factor of $x^{3}+8$ is $(x+2)(x^{2}-2x+4)$

Step-by-step explanation:

We need to factorise the given expression $x^{3}+8$

Re-write the expression $x^{3}+8$ as:

$x^{3}+2^{3}$

Since, $a^{3}+b^{3}=(a+b)(a^{2}-ab+b^{2})$

so, here a = x and b = 2

$(x+2)(x^{2}-2x+2^{2})$

$(x+2)(x^{2}-2x+4)$

Hence, The factor of $x^{3}+8$ is $(x+2)(x^{2}-2x+4)$