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2 years ago

12

2 questions! area of plane and composite figures

1 answer:

VikaD [51]2 years ago

4 0

Find the base and height of each side, subtract the triangle from the trapezoid then find the area of the parrellogram and add the subracted one and the obtuse square

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Kendall ate g out of 11 gumdrops. Write an expression that shows how many gumdrops Kendall has left.

liq [111]

Answer:

11-g

Step-by-step explanation:

You would have to subtract the number of gumdrops Kendall ate (g) from the number of gumdrops they had in the beginning (11). So the expression would be 11-g

8 0

3 years ago

Andrea has some money. Her brother gives her 7 coins worth 23 cents and now she has 73 cents. If she started with 5 coins, what

Nat2105 [25]

Andrea had 5 coins worth 50 cents ! And , thereafter her brother gave her 7 coins worth 23 cents .

<u>Step-by-step explanation:</u>

Here we have , Andrea has some money. Her brother gives her 7 coins worth 23 cents and now she has 73 cents. If she started with 5 coins, We need to find what coins did Andrea's brother give her and what coins did Andrea start with. Let's find out:

Andrea has some money , and her brother gives her 7 coins ! worth 23 cents . So , 1 coin worth is :

⇒ $\frac{23}{7}$

⇒ $3.29cents$

Now , she had a total of 73 cents i.e.

⇒ $73 = x+23$

⇒ $x=50$

Initially Andrea had 5 coins worth 50 cents ! And , thereafter her brother gave her 7 coins worth 23 cents .

3 0

3 years ago

Yana plans to run 1 mile she has run 7/10 of a mile what fraction of a mile does she have left to run

Andre45 [30]

Answer:

3/10

Step-by-step explanation:

7+3= 10 so 7+3=10/10 which is one mile

8 0

3 years ago

5u-2u=..................................................

MAVERICK [17]

It will be 3u good luck

8 0

2 years ago

Find the solutions to x⁴-5x²-36=0 and the x-intercepts of the graph of y=x⁴-5x²-36.

disa [49]

Answer:

The solutions $x^4-5x^2-36=0$ are $x=3,\:x=-3,\:x=2i,\:x=-2i$ and the x-intercepts of $y=x^4-5x^2-36$ are $x=3,\:x=-3$

Step-by-step explanation:

Finding the solutions to $x^4-5x^2-36$ means finding the roots, a root is where the function is equal to zero.

The x-intercept is the point at which the graph crosses the x-axis. At this point, the y-coordinate is zero.

To find the roots you need to:

Rewrite the equation with $u=x^2$ and $u^2=x^4$

$u^2-5u-36=0$

Solve by factoring

$\mathrm{Break\:the\:expression\:into\:groups}\\u^2-5u-36=\left(u^2+4u\right)+\left(-9u-36\right)$

$\mathrm{Factor\:out\:}u\mathrm{\:from\:}u^2+4u=u\left(u+4\right)$

$\mathrm{Factor\:out\:}-9\mathrm{\:from\:}-9u-36=-9\left(u+4\right)$

$u^2-5u-36=u\left(u+4\right)-9\left(u+4\right)$

$\mathrm{Factor\:out\:common\:term\:}u+4\\\left(u+4\right)\left(u-9\right)$

$u^2-5u-36=\left(u+4\right)\left(u-9\right)=0$

Using the Zero factor Theorem: if ab = 0 then a = 0 or b = 0 (or both a = 0 and b = 0)

The solutions to the quadratic equation are:

$\:u=-4,\:u=9$

Substitute back $u=x^2$ , solve for x

$x^4-5x^2-36=(u-9)(u+4)=(x^2-9)(x^2+4)$

Apply the difference of squares formula

$x^4-5x^2-36=(x^2-9)(x^2+4)=(x-3)(x+3)(x^2+4)$

$(x-3)(x+3)(x^2+4)=0$

Using the Zero factor Theorem: if ab = 0 then a = 0 or b = 0 (or both a = 0 and b = 0)

The solutions are:

$\:x=3,\:x=-3,\:x=2i,\:x=-2i$

Because two of the solutions are complex roots the only x-intercepts are $x=3,\:x=-3$

3 0

3 years ago