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3 years ago

The perimeter of a rectangular photograph is 28 inches. If the width of the photo is 5 inches, how tall is the photo?

Mathematics

2 answers:

svetoff [14.1K]3 years ago

8 0

Answer:

9 inches.

Step-by-step explanation:

Since the width of the rectangle is 5 inches, We have to times it by 2 which is 10.

Then deduct it from the perimeter of 28, which equals to 18. We have to divide it by 2 so we can find out how tall each side is. 18 divided by 2=9.

Hope that helps.

Advocard [28]3 years ago

6 0

Answer:

it is 9 inches tall

Step-by-step explanation:

p=2L + 2W

28=2L + 2 x 5

28=2L +10

28-10=2L

18=2L

L=9

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Find the unknown factor.

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The answers is -7/6x

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2 years ago

What is the equation of the line that is parallel to 8x-5y=2 and goes through the point (-5,-2)

Stella [2.4K]

Answer:

8x - 5y = - 30

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Rearrange 8x - 5y = 2 into this form

Subtract 8x from both sides

- 5y = - 8x + 2 ( divide all terms by - 5 )

y = $\frac{8}{5}$ x - $\frac{2}{5}$ ← in slope- intercept form

with slope m = $\frac{8}{5}$

• Parallel lines have equal slopes, hence

y = $\frac{8}{5}$ x + c ← is the partial equation of the parallel line

To find c substitute (- 5, - 2) into the partial equation

- 2 = - 8 + c ⇒ c = - 2 + 8 = 6

y = $\frac{8}{5}$ x + 6 ← in slope- intercept form

Multiply through by 5

5y = 8x + 30 ( subtract 5y from both sides )

0 = 8x - 5y + 30 ( subtract 30 from both sides )

8x - 5y = - 30 ← in standard form

3 0

3 years ago

If 29% of the students wore jeans what percent of he students did not wear jeans?

igor_vitrenko [27]

So you just take 100% - 29% = 71%

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7 0

2 years ago

GIVEN: LJ || WK || AP, PL || AG.

galina1969 [7]

Answer:

∠1 ≅ ∠2 ⇒ proved down

Step-by-step explanation:

#12

In the given figure

∵ LJ // WK

∵ LP is a transversal

∵ ∠1 and ∠KWP are corresponding angles

∵ The corresponding angles are equal in measures

∴ m∠1 = m∠KWP

∴ ∠1 ≅ ∠KWP ⇒ (1)

∵ WK // AP

∵ WP is a transversal

∵ ∠KWP and ∠WPA are interior alternate angles

∵ The interior alternate angles are equal in measures

∴ m∠KWP = m∠WPA

∴ ∠KWP ≅ ∠WPA ⇒ (2)

→ From (1) and (2)

∵ ∠1 and ∠WPA are congruent to ∠KWP

∴ ∠1 and ∠WPA are congruent

∴ ∠1 ≅ ∠WPA ⇒ (3)

∵ WP // AG

∵ AP is a transversal

∵ ∠WPA and ∠2 are interior alternate angles

∵ The interior alternate angles are equal in measures

∴ m∠WPA = m∠2

∴ ∠WPA ≅ ∠2 ⇒ (4)

→ From (3) and (4)

∵ ∠1 and ∠2 are congruent to ∠WPA

∴ ∠1 and ∠2 are congruent

∴ ∠1 ≅ ∠2 ⇒ proved

8 0

2 years ago

Suppose a circle with center (14,9) passes through point (16, 12). Which equation represents the circle?

kifflom [539]

Answer:

( x - 14)^2 + ( y - 9)^2 = 13

Step-by-step explanation:

The equation of the circle with a center and a point

( x - a) ^2 + ( y - b) ^2 = r^2

( 14 , 9) - center-( a, b)

a = 14

b = 9

( 16 , 12) - point - ( x, y)

x = 16

y = 12

Step 1: substitute the center into the equation

( x - 14)^2 + ( y - 9)^2 = r^2

Step 2: substitute the point into the equation

( x - 14)^2 +( y - 9)^2 = r^2

( 16 - 14)^2 + ( 12 - 9)^2 = r^2

2^2 + 3^2 = r^2

4 + 9 = r^2

13 = r^2

Step 3: subs the radius into the equation

( x - 14)^2 + ( y - 9)^2 = r^2

( x - 14)^2 + (y - 9)^2 = 13

Therefore, the equation of the circle is

( x - 14)^2 + ( y - 9)^2 = 13

8 0

3 years ago