Answer:
C, The marble is 3 times as likely to be black as it is to be white.
Step-by-step explanation:
The probability of a marble being drawn is:
number of marbles of that color/total number of marbles
Find total number of marbles
5+8+4+15= 35
So the probability of drawing:
white: 5/32
polka dot: 8/32
striped: 4/32
black: 15/32
The probability of drawing white, polka dot, or striped is obviously different, so A is wrong.
The probability of drawing every color but black is 5/32 + 8/32 + 4/32 = 17/32, which is more than the chance of drawing black, so B is wrong.
The probability of drawing black is 15/32, and that is 3 times larger than the probability of drawing white (5/32), so C is correct.
The probablility of drawing a polka dot is 8/32, which is not four times as large as stripe (4/32), so D is wrong.
175-150=25,,(25/175)*100==14.29
When I did the math I came up as 3.88 but if you have to round up it wound be 4 or 3.9
Answer:
Probability of at least two cuckoo eggs is 0.738.
Step-by-step explanation:
probability of cuckoo egg = 0.1
probability of not a cuckoo egg = 1 - 0.1 = 0.9
Probability of at least two cuckoo eggs is
= Probability of two cuckoo eggs x probability of 1 not cuckoo egg +
probability of three cuckoo eggs
= 0.1 x 0.1 x 0.9 + 0.9 x 0.9 x 0.9
= 0.009 + 0.729
= 0.738
The confidence interval formula is computed by:
Xbar ± Z s/ sqrt (n)
Where:
Xbar is the mean
Z is the z value
S is the standard deviation
N is the number of samples
So our given are:
90% confidence interval with a z value of 1.645
Sample size 40, 45
Mean 180, 179
Standard deviation 2, 4
So plugging that information in the data will give us a
confidence interval:
For 1:
Xbar ± Z s/ sqrt (n)
= 180 ± 1.645 (2 / sqrt (40))
= 180 ± 1.645 (0.316227766)
= 180 ± 0.520194675
= 179.48, 180.52
For 2:
Xbar ± Z s/ sqrt (n)
= 179 ± 1.645 (4 / sqrt (45))
<span>= 179 ± 1.645 (0.596284794)</span>
therefore, the answer is letter b
