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Elena-2011 [213]
3 years ago
10

Help if you answer I’ll mark you brainliest

Mathematics
2 answers:
Delicious77 [7]3 years ago
8 0

Answer:

I CAN'T SEE ANYTHING FROM THAT FAR SORRY BUT I WISH I COULD HELP YOU!!!

Step-by-step explanation:

(again sorry)!

satela [25.4K]3 years ago
5 0

Answer:

1 = 1.3

2 = 2.25

3 = 9/100

4 = 3/4

5 = 31

6 = <

Step-by-step explanation:

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45 divided by 9 = 5
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How do i solve this?
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Graph this down below​
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Estimate the answer to 341÷28
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Find the solution of the differential equation that satisfies the given initial condition. y' tan x = 3a + y, y(π/3) = 3a, 0 &lt
Paladinen [302]

Answer:

y(x)=4a\sqrt{3}* sin(x)-3a

Step-by-step explanation:

We have a separable equation, first let's rewrite the equation as:

\frac{dy(x)}{dx} =\frac{3a+y}{tan(x)}

But:

\frac{1}{tan(x)} =cot(x)

So:

\frac{dy(x)}{dx} =cot(x)*(3a+y)

Multiplying both sides by dx and dividing both sides by 3a+y:

\frac{dy}{3a+y} =cot(x)dx

Integrating both sides:

\int\ \frac{dy}{3a+y} =\int\cot(x) \, dx

Evaluating the integrals:

log(3a+y)=log(sin(x))+C_1

Where C1 is an arbitrary constant.

Solving for y:

y(x)=-3a+e^{C_1} sin(x)

e^{C_1} =constant

So:

y(x)=C_1*sin(x)-3a

Finally, let's evaluate the initial condition in order to find C1:

y(\frac{\pi}{3} )=3a=C_1*sin(\frac{\pi}{3})-3a\\ 3a=C_1*\frac{\sqrt{3} }{2} -3a

Solving for C1:

C_1=4a\sqrt{3}

Therefore:

y(x)=4a\sqrt{3}* sin(x)-3a

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