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Slav-nsk [51]
3 years ago
10

Can anyone solve ? This one is beyond me

Mathematics
1 answer:
Makovka662 [10]3 years ago
5 0

Answer:

Rate = 0.13

Step-by-step explanation:

Given

y = \sqrt[3] x

Required

Determine the average rate of change over [2,7]

This is calculated as:

Rate = \frac{f(b) - f(a)}{b - a}

In this case:

b = 7 and a = 2

So, we have:

Rate = \frac{f(7) - f(2)}{7-2}

Rate = \frac{f(7) - f(2)}{5}

From the table:

f(7) = 1.91

f(2) = 1.26

Rate = \frac{1.91 - 1.26}{5}

Rate = \frac{0.65}{5}

Rate = 0.13

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Answer:

answer above is wrong, correct answer is $2.50 or B on edge 2020

Step-by-step explanation:

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3 years ago
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Which expression is equivalent to...? Assume... screenshots attached, please help!
larisa [96]

Answer:

\frac{\sqrt[3]{5} }{3x}

Step-by-step explanation:

Ok, let's do this step by step....

\sqrt[3]{\frac{10x^{5} }{54x^{8} } }

Let's first simplify the x's:

\sqrt[3]{\frac{10}{54x^{3} } }

Then we breakdown the 54 as 2 * 27 then simplify with the 10 above.

\sqrt[3]{\frac{10}{2 * 27x^{3} } } = \sqrt[3]{\frac{5}{27x^{3} } }

Now, we can rewrite this as the following and solve the bottom part:

\frac{\sqrt[3]{5} }{\sqrt[3]{27x^{3} } } = \frac{\sqrt[3]{5} }{3 \sqrt[3]{x^{3} } } = \frac{\sqrt[3]{5} }{3x}

The solution is

\frac{\sqrt[3]{5} }{3x}

8 0
4 years ago
HELP ASAP!!! What is the area of this trapezoid? (I will thank)
Alekssandra [29.7K]

Answer:

88 u²

Step-by-step explanation:

The formula for the area of a trapezoid is:

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Given the measurements in the diagram:

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Plug them into the equation: A = \frac{1}{2}(4)(17 + 27) = 88 units²

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3 years ago
What is the area of this figure?
Igoryamba

Answer:

70

Step-by-step explanation:

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