Answer:
Plant B
Step-by-step explanation:
The only measure of variation we really need to check is the mean, or average, of tomatoes that each plant produced. This is because if Kathryn was a farmer, she would want a plant that on average, produces more tomatoes. For that reason, in this context, the mode, median and range are irrelevant. To find the mean of a data set, you simply divide the sum of all of the data by the number of data in the set. Therefore:
Mean of Plant A: (4 + 6 + 7 + 3 + 6 + 2 + 1 + 3 + 6 + 5) / 10 = 43 / 10 = 4.3
Mean of Plant B: (5 + 6 + 7 + 6 + 8 + 9 + 6 + 7 + 8 + 9) / 10 = 71 / 10 = 7.1
As you can see, the mean tomatoes Plant B produces is larger than that of Plant A, therefore, Kathryn should choose Plant B if she was a farmer.
Answer:
a = 0, b = -15
Step-by-step explanation:
Given two complex number Z1=3cispi and z2=5cis(pi/2)
In polar form;
z1 = 3(cospi + isinpi)
z1 = 3(-1+i0)
z1 = -3+0i
Z2 = 5(cospi/2 + isinpi/2)
Z2 = 5(0+i)
Z2 = 0+5i
Z1*Z2 = (-3+0i)(0+5i)
Z1*Z2 = 0 - 15i +0i + 0i²
Z1*Z2 = 0-15i
comparing 0-15i with a + bi;
a = 0 and b = -15
According to the system:
5 – 7x + 2y² = -10
1 – 5x – 2y = -22
______________
a) No ; (4, 6) is not a solution to the
system. This point does not touch either equation.
b) No ; (6, 4) is not a solution to the system. This point does not touch either equation.
Solutions:
x = ( 122 ∓ 3√101 ) / 25 ≈ 3.674 or 6.086
y = ( -7 ± 3√101 ) / 10 ≈ 2.315 or -3.715
Hi,
Answer: (x+5)^2
<u>My work:</u> For this problem can be easily achieved by factoring your terms. To do this you figure out what can go into 10x and 25 which is 5. From the there you take x^2 and 10x and see what can take out which would be x. Your answer would be (x + 5)^2 or (x +5) (x + 5). This can be done in 2 easy steps!
<u><em>Numerical work:</em></u>
1.x^2 10x +25
Before this step figure out what goes into you equation.
2. (X + 5)^2 or (X+5) (X + 5)
circumference of circle= 2x3.14r
1) radius is 9
2x3.14x9
18x3.14= 56.52
2) radius is 8
2x3.14x8
16x3.14= 50.24
3) radius is 5
2x3.14x5
10x3.14= 31.4
