Answer:
95% Confidence interval = (23.4,26.2)
Step-by-step explanation:
In this problem we have to develop a 95% CI for the mean.
The sample size is n=49, the mean of the sample is M=24.8 and the standard deviation of the population is σ=5.
We know that for a 95% CI, the z-value is 1.96.
The CI is

Answer:
2(n - 6) >= 22
Step-by-step explanation:
2n - 12 >= 22
2n >= 22+12
2n >= 34
n >= 34/2
n >= 17
Answer:
<h2>a = 400/21, b = 580/21</h2>
Step-by-step explanation:
Small triangles are similar. Therefore, the sides are proportional
<em>cross multiply</em>
<em>divide both sides by 21</em>

For b, we can use the Pythagorean theorem:

Answer:
uuh The a is equal to 16
Step-by-step explanation: