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ioda
3 years ago
8

Karen is working on her math homework. She solves the equation

Mathematics
1 answer:
Gelneren [198K]3 years ago
5 0
Disagree.
b/8 = 56; multiply both sides by 8 to solve for b, and you get b = 448
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14=3/8 find the quotient
ANTONII [103]

Answer:

The equation is always false

Step-by-step explanation:

5 0
3 years ago
Can somebody help me with this question please ?
inysia [295]

Answer: No.

Step-by-step explanation: g should also be factored out. 10g(a - 3z).

4 0
3 years ago
How do you solve 3x+7=x
vredina [299]
3x + 7 = x

First, subtract 3x from both sides. / Your problem should look like: 7 = x - 3x
Second, simplify x - 3x to -2x. / Your problem should look like: 7 = -2x
Third, divide both sides by -2. / Your problem should look like: \frac{7}{-2} = x
Fourth, simplify \frac{7}{-2} to -\frac{7}{2} / Your problem should look like: - \frac{7}{2} = x
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Answer as decimal: -3.5


8 0
3 years ago
Read 2 more answers
Help, please the question and thank you
Fynjy0 [20]

Answer:

2

Step-by-step explanation:

If A = (2, 3) then a dilation of scale factor 2 means that the x and y coordinates are multiplied by 2, so x = 2 x 2 = 4  and y = 3 x 2 = 6, so A' = (4, 6)

8 0
2 years ago
for the given license plate configuration, determine how many different plates are possinle if letters and digits (a) can ba rep
Inessa05 [86]

Answer:

a) 1,757,600 different plates possible.

b) 1,404,000 different plates possible.

Step-by-step explanation:

The permutations formula is important to solve this question.

Permutations formula:

The number of possible permutations of x elements from a set of n elements is given by the following formula:

P_{(n,x)} = \frac{n!}{(n-x)!}

(a) can be repeated:

There are 3 letters, each one with 26 possible outcomes.

2 digits, each with 10 possible outcomes

So

T = 26*26*26*10*10 = 1757600

1,757,600 different plates possible.

(b) cannot be repeated:

Here the permutations formula is used.

Three letters, from a set of 26.

Two digits, from a set of 10. So

T = P_{(26,3)}*P_{(10,2)} = \frac{26!}{(26-3)!}*\frac{10!}{(10-2)!} = 1404000

1,404,000 different plates possible.

4 0
3 years ago
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