Answer:
Option A:
Number of seats
Step-by-step explanation:
A discrete quantitative variable is a variable that can be enumerated. This means that they are in units in which numbers can be assigned to and can be counted.
The number of seats present in the car can be counted. This feature can also be evaluated based on its numeral value, rather than its quality. In a simple form, the buyers feel that the more the number of seats present in the car, the more people it can carry. Hence, the family would love to buy a car with a good number of seats in it.
The other features in the options are rather continuous, qualitative, or boolean. Some of them are continuous because they cannot be counted e.g fuel efficiency. The others such as the presence of a sunroof can be seen as a boolean variable. (it can either be true or false)
Type of the transmission is a qualitative variable
First, a bit of housekeeping:
<span>The meaning of four consecutive even numbers is 15. Wouldn't that be "mean," not meaning? Very different concepts!
The greatest of these numbers is _______ a^1
"a^1" means "a to the first power. There are no powers in this problem statement. Perhaps you meant just "a" or "a_1" or a(1).
The least of these numbers is ______a^2.
No powers in this problem statement. Perhaps you meant a_2 or a(2)
In this problem you have four numbers. All are even, and there's a spacing of 2 units between each pair of numbers (consecutive even).
The mean, or arithmetic average, of these numbers is (a+b+c+d) / 4, where a, b, c and d represent the four consecutive even numbers. Here this mean is 15. The mean is most likely positioned between b anc c.
So here's what we have: a+b+c+d
------------- = 15
4
This is equivalent to a+b+c+d = 60.
Since the numbers a, b, c and d are consecutive even integers, let's try this:
a + (a+2) + (a+4) + (a+6) = 60. Then 4a+2+4+6=60, or 4a = 48, or a=12.
Then a=12, b=14, c=16 and d=18. Note how (12+14+16+18) / 4 = 15, which is the given mean.
We could also type, "a(1)=12, a(2)=14, a(3) = 16, and a(4) = 18.
</span>
F(n)=3n
f(1/3)=3(1/3)
f(1/3)=1
Hope I didn't mess up for your sake
3y = 5x + 30
y + 5x = 50 .......(1)
3y - 5x = 30 .....(2) - rearranging the first equation.
Add (1) and (2):-
4y = 80
y = 20
Now plug y = 20 into equation (1):-
20 + 5x = 50
5x = 30
x = 6
The 2 numbers are 6 and 20.
You are correct there's at least one obtuse angle
