X^3 = 216
by taking cubic root for both sides
![\sqrt[3]{x^3} = \sqrt[3]{216}](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7Bx%5E3%7D%20%3D%20%20%5Csqrt%5B3%5D%7B216%7D%20)
x = 6
5n + 7 = 7(n+1) - 2n
First distribute 7 to all terms inside the parenthesis
7(n) = 7n
7(1) = 7
5n + 7 = 7n - 2n + 7
Simplify. Combine like terms
5n + 7 = 5n + 7
True.
If you want to continue:
Isolate the n, move all variables to one side, and constants to the other
5n (-5n) + 7 (-7) = 5n (-5n) + 7 (-7)
0 = 0
True
hope this helps
Answer:
A-100
Step-by-step explanation:
Use the Pythagorean therom.
a^2+b^2=c^2
6^2+8^2=c^2
36+64=100.
Hope this helps. Kinda confused me.
Answer:
W = -3
Step-by-step explanation:
Answer:
SAS
Step-by-step explanation:
Given: Two triangles ΔABD and ΔDCA,
We have, AD=AD (normal)
∠A=∠A (Given)
BA=CD (Sides inverse to rise to points are consistently equivalent)
With the SAS rule of congruency,
ΔABD≅ΔDCA
Brainliest?
