Answer:
10.439 Km
Step-by-step explanation:
Answer:
110 fence posts
Step-by-step explanation:
102÷6=17
multiply by 2 = 34
330÷6=55
multiply by 2=110
add together= 144 fence posts
The probability of event A and B to both occur is denoted as P(A ∩ B) = P(A) P(B|A). It is the probability that Event A occurs times the probability that Event B occurs, given that Event A has occurred.
So, to find the probability that you will be assigned a poem by Shakespeare and by Tennyson, let Event A = the event that a Shakespeare poem will be assigned to you; and let Event B = the event that the second poem that will be assigned to you will be by Tennyson.
At first, there are a total of 13 poems that would be randomly assigned in your class. There are 4 poems by Shakespeare, thus P(A) is 4/13.
After the first selection, there would be 13 poems left. Therefore, P(B|A) = 2/12
Based on the rule of multiplication,
P(A ∩ B) = P(A) P(B|A)P(A ∩ B) = 4/13 * 2/12
P(A ∩ B) = 8/156
P(A ∩ B) = 2/39
The probability that you will be assigned a poem by Shakespeare, then a poem by Tennyson is 2/39 or 5.13%.
Given:
The equation is 
.
To find:
The scenario that uses the given equation.
Solution:
If p is the price of a good. Initial supply of goods at price 0 is 10 and supply increasing by 7 units if the price increased by 1 unit, then at what price the supply will be 24 units.
According to this scenario,
Total supply = 10+7p
Equate total supply with 24, to find the price at which the supply will be 24 units.
Therefore, the required scenario is "If p is the price of a good. Initial supply of goods at price 0 is 10 and supply increasing by 7 units if the price increased by 1 unit, then at what price the supply will be 24 units."
