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trasher [3.6K]
3 years ago
10

Applying Inverse Properties In Exercise,apply the inverse properties of logarithmic and exponential functions to simplify the ex

pression.See example 2.
- 1 + In e2x
Mathematics
1 answer:
alex41 [277]3 years ago
6 0

Answer:

2x - 1

Step-by-step explanation:

Since logarithm has the following property:

If f(x)=b^x and g(x)=\log_bx,

Then fog=b^{\log_bx}=x and gof=\log_bbx=x

Therefore,

- 1 + \ln e^{2x} = - 1 + \log_e e^{2x} = 2x-1

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jonathan ran 5 days this week. the most he ran in one day was 3.5 miles. write an inequality that shows the distance jonathan co
poizon [28]
Let m represent the number of miles this guy runs in a day.
He runs every day, so the minimum number of miles has to be greater than 0.
According to the problem statement, the max number of miles is 3.5 miles or less.

Translate this into a (symbolic) inequality.
4 0
3 years ago
Mikaela purchased a paddleboard originally priced at $699. If all merchandise was on sale for 40% off and the state tax rate is
vitfil [10]

Answer:

299.87

Step-by-step explanation:

699*0.40=279.60\\279.60*0.0725= 20.271 (round)\\279.60+20.27=299.87

6 0
2 years ago
Read 2 more answers
Geometry...Please help as soon as possible please and Thank you!!!
Kaylis [27]

Answer:

I answered the question according to "ASA" Angle, side, angle

.....

Step-by-step explanation:

Note : I'm not a teacher but I'm quite sure about my answer...

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4 0
2 years ago
Complete a table with at least 5 points then graph the following quadratic on the coordinate plane. Identify all zeros.y = -2x2
Anna [14]

Answer:

See attached

Step-by-step explanation:

Given function:

  • y = -2x² + 5x + 8

Table and graph are attached

Zeros are included in the graph

<u>Zero's are obtained:</u>

x = 0 ⇒ y = 8

y = 0 ⇒  Solving quadratic equation

  • -2x² + 5x + 8 = 0
  • x = (-5 ± √(25 + 2*4*8))/-4
  • x = 3.608
  • x = -1.108

So zeros are (0, 8), (3.608, 0) and (-1.108, 0)

3 0
3 years ago
Please Help !!!
solong [7]
Best Answer: 2 LiCl = 2 Li + Cl2
mass Li = 56.8 mL x 0.534 g/mL=30.3 g
moles Li = 30.3 g / 6.941 g/mol=4.37
the ratio between Li and LiCl is 2 : 2 ( or 1 : 1)

moles LiCl required = 4.37
mass LiCl = 4.37 mol x 42.394 g/mol=185.3 g


Cu + 2 AgNO3 = Cu/NO3)2 + 2 Ag
the ratio between Cu and AgNO3 is 1 : 2
moles AgNO3 required = 4.2 x 2 = 8.4 : but we have only 6.3 moles of AgNO3 so AgNO3 is the limiting reactant
moles Cu reacted = 6.3 / 2 = 3.15
moles Cu in excess = 4.2 - 3.15 =1.05

N2 + 3 H2 = 2 NH3
moles N2 = 42.5 g / 28.0134 g/mol=1.52
the ratio between N2 and H2 is 1 : 3
moles H2 required = 1.52 x 3 =4.56
actual moles H2 = 10.1 g / 2.016 g/mol= 5.00 so H2 is in excess and N2 is the limiting reactant
moles NH3 = 1.52 x 2 = 3.04
mass NH3 = 3.04 x 17.0337 g/mol=51.8 g
moles H2 in excess = 5.00 - 4.56 =0.44
mass H2 in excess = 0.44 mol x 2.016 g/mol=0.887 g
5 0
4 years ago
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