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BlackZzzverrR [31]

3 years ago

5

An art teacher has 192 containers of paint for 17 students. If the teacher wants to provide each student with an equal amount of

containers how many containers would be left over

1 answer:

guapka [62]3 years ago

7 0

Answer: 5 containers

Step-by-step explanation:

Total containers= 192

Total students= 17

Each student will get, 192/17 = 11 5/17.

Each student gets 11 containers of paint and there'll be 5 left.

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Standard Error from a Formula and a Bootstrap Distribution Sample A has a count of 30 successes with and Sample B has a count of

tia_tia [17]

Answer:

Using a formula, the standard error is: 0.052

Using bootstrap, the standard error is: 0.050

Comparison:

The calculated standard error using the formula is greater than the standard error using bootstrap

Step-by-step explanation:

Given

Sample A Sample B

$x_A = 30$ $x_B = 50$

$n_A = 100$ $n_B =250$

Solving (a): Standard error using formula

First, calculate the proportion of A

$p_A = \frac{x_A}{n_A}$

$p_A = \frac{30}{100}$

$p_A = 0.30$

The proportion of B

$p_B = \frac{x_B}{n_B}$

$p_B = \frac{50}{250}$

$p_B = 0.20$

The standard error is:

$SE_{p_A-p_B} = \sqrt{\frac{p_A * (1 - p_A)}{n_A} + \frac{p_A * (1 - p_B)}{n_B}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.30 * (1 - 0.30)}{100} + \frac{0.20* (1 - 0.20)}{250}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.30 * 0.70}{100} + \frac{0.20* 0.80}{250}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.21}{100} + \frac{0.16}{250}}$

$SE_{p_A-p_B} = \sqrt{0.0021+ 0.00064}$

$SE_{p_A-p_B} = \sqrt{0.00274}$

$SE_{p_A-p_B} = 0.052$

Solving (a): Standard error using bootstrapping.

Following the below steps.

Open Statkey
Under Randomization Hypothesis Tests, select Test for Difference in Proportions
Click on Edit data, enter the appropriate data
Click on ok to generate samples
Click on Generate 1000 samples ---- <em>see attachment for the generated data</em>

From the randomization sample, we have:

Sample A Sample B

$x_A = 23$ $x_B = 57$

$n_A = 100$ $n_B =250$

$p_A = 0.230$ $p_A = 0.228$

So, we have:

$SE_{p_A-p_B} = \sqrt{\frac{p_A * (1 - p_A)}{n_A} + \frac{p_A * (1 - p_B)}{n_B}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.23 * (1 - 0.23)}{100} + \frac{0.228* (1 - 0.228)}{250}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.1771}{100} + \frac{0.176016}{250}}$

$SE_{p_A-p_B} = \sqrt{0.001771 + 0.000704064}$

$SE_{p_A-p_B} = \sqrt{0.002475064}$

$SE_{p_A-p_B} = 0.050$

5 0

3 years ago

Solve for x<br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B4x%20-%206%7D%7B4%7D%20%20%3D%20%20%5Cfrac%7B2x%20%2B%205%7D%7B3%7

Marizza181 [45]

Answer:

x = 9.5

Step-by-step explanation:

Given

$\frac{4x-6}{4}$ = $\frac{2x+5}{3}$ ( cross- multiply )

3(4x - 6) = 4(2x + 5) ← distribute parenthesis on both sides

12x - 18 = 8x + 20 ( subtract 8x from both sides )

4x - 18 = 20 ( add 18 to both sides )

4x = 38 ( divide both sides by 4 )

x = $\frac{38}{4}$ = 9.5

6 0

3 years ago

Jack and Jill were buying water jugs jack bought 2 medium sized jugs and 3 large sized jugs for 150 dollars and Jill bought 4 me

Mademuasel [1]

Answer: the cost of one medium sized jug is $60

the cost of one large sized jug is $10

Step-by-step explanation:

Let x represent the cost of one medium sized jug.

Let y represent the cost of one large sized jug.

Jack bought 2 medium sized jugs and 3 large sized jugs for 150 dollars. This means that

2x + 3y = 150 - - - - - - - - - - - 1

Jill bought 4 medium jugs and 12 large jugs for 360 dollars. This means that

4x + 12y = 360 - - - - - - - - - - - 2

Multiplying equation 1 by 4 and equation 2 by 2, it becomes

8x + 12y = 600

8x + 24y = 720

Subtracting, it becomes

- 12y = - 120

y = - 120/ - 12

y = 10

Substituting y = 10 into equation 1, it becomes

2x + 3 × 10 = 150

2x + 30 = 150

2x = 150 - 30 = 120

x = 120/2 = 60

3 0

3 years ago

X – 6 = -3x^2<br><br> Need help!!

alex41 [277]

this is answer for your problem

8 0

3 years ago

Read 2 more answers

Martin has 4 tickets to ICe Fantasy with the Stars. They cost him $15.75 each, plus $3.50 in handling per ticket, and $9.50 in s

Sergio039 [100]

Each ticket cost $15.75, and each ticket paid $3.50 handling,
so each ticket cost $15.75 + $3.50 = $19.25.

There are 4 tickets, so the 4 tickets including handling
cost 4 * $19.25 = $77.00

The shipping fee is a single fee for all the tickets,
so you just add $9.50 to $77.
The total cost is $77.00 + $9.50 = $86.50

4 0

3 years ago

Read 2 more answers