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In-s [12.5K]
3 years ago
13

In a probability experiment, Craig rolled a six-sided die 64 times. The die landed on a number greater than three 39 times. What

is the ratio of rolls greater than three to rolls less than or equal to three?
A.


B.


C.


D.
Mathematics
1 answer:
Charra [1.4K]3 years ago
7 0

Answer:

The ratio is 34/22, or in simplest form, 17/11.

Step-by-step explanation:

We write the ratio with the number of rolls greater than three on top and the number of rolls less than or equal to 3 on bottom:

34/(56-34)

We have to subtract 34 from 56 to find out how many rolls were less than or equal to 3.

34/22

Both are divisible by 2, so we have 17/11.

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Solve the following system:
{7 x - 3 y = 37 | (equation 1)
{14 x + 11 y = 23 | (equation 2)
Swap equation 1 with equation 2:
{14 x + 11 y = 23 | (equation 1)
{7 x - 3 y = 37 | (equation 2)
Subtract 1/2 × (equation 1) from equation 2:
{14 x + 11 y = 23 | (equation 1)
{0 x - (17 y)/2 = 51/2 | (equation 2)

Multiply equation 2 by 2/17:
{14 x + 11 y = 23 | (equation 1)
{0 x - y = 3 | (equation 2)

Multiply equation 2 by -1:
{14 x + 11 y = 23 | (equation 1)
{0 x+y = -3 | (equation 2)
Subtract 11 × (equation 2) from equation 1:
{14 x+0 y = 56 | (equation 1)
{0 x+y = -3 | (equation 2)

Divide equation 1 by 14:
{x+0 y = 4 | (equation 1)
{0 x+y = -3 | (equation 2)
Collect results:
Answer: {x = 4
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Step-by-step explanation:

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