Phythagoras theorem:
hypotenuse²=leg₁²+leg₂²
Data:
leg₂=7.2
hypotenuse=11.1
Therefore:
(11.1)₂=leg₁² +(7.2)²
123.21=leg₁²+51.84
leg₁²=123.21 - 51.84
leg₁²=71.37
leg¹=√(71.37)
leg₁=8.4
Answer: b=8.4
The question is incomplete. The complete question is :
A bulb can either be on or off. A board contains 20 bulbs connected to a randomization circuit that lights up a random sequence every time it is turned on. What is the probability that all the lights will switch on ?
Solution :
It is given that :
There is board connected to = 20 bulbs
And one can either be put ON or put OFF.
Therefore the chance that a bulb is ON = 
It is given that every time a bulb turns ON, the board lights up in a random sequence.
Therefore, the probability of all the lights to be switched ON is given by :


The answer to this is ...
D. (-1, 5)
Hope this helped! <3
Answer:
2(3x+4y)
Step-by-step explanation:
2 doubles it
5x3=15 3x2=6 15x6=90 So your answer is 90.