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irinina [24]
3 years ago
7

How many times is "Alert" displayed in the following loop? for (int k =0; k<= 100; k++) cout << "Alert"; O 101 0 1 oo О

99 O 100
Computers and Technology
1 answer:
andrew11 [14]3 years ago
7 0

Answer:

Hi, the answer is 100

Explanation:  

In this case we have in the second parameter of the loop the condition to stop (k <= 100)  it's means the iteration start at  k=0 until k is less or equal to 100, in those iterations you get in the output (AlertAlertAlertAlert...)

I hope it's help you.

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create your own min function that finds the minimum element in a list and use it in a separate function
schepotkina [342]

Answer:

def minfunction(mylist):

   min = mylist[0]

   for i in mylist:

       if i < min:

           min = i

   print("The minimum is: "+str(min))

   

def anotherfunction():

   mylist = []

   n = int(input("Length of list: "))

   for i in range(n):

       listelement = int(input(": "))

       mylist.append(listelement)

   minfunction(mylist)

   

anotherfunction()

Explanation:

This solution is implemented in Python

This defines the min function

def minfunction(mylist):

This initializes the minimum element to the first index element

   min = mylist[0]

This iterates through the list

   for i in mylist:

This checks for the minimum

       if i < min:

... and assigns the minimum to variable min

           min = i

This prints the minimum element

   print("The minimum is: "+str(min))

   

This defines a separate function. This  separate function is used to input items into the list

def anotherfunction():

This defines an empty list

   mylist = []

This prompts user for length of list

   n = int(input("Length of list: "))

The following iteration inputs elements into the list

<em>    for i in range(n):</em>

<em>        listelement = int(input(": "))</em>

<em>        mylist.append(listelement)</em>

This calls the minimum function

   minfunction(mylist)

   

The main starts here and this calls the separate function

anotherfunction()

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3 years ago
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