Question

Suppose there are 4 nodes sharing a broadcast channel using TDMA protocol. Suppose at time t=0: • Node 1 has 6 frames to transmit, • Node 2 has 4 frames to transmit, • Node 3 has 8 frames to transmit, • Node 4 has 3 frames to transmit. Maximum number of frames which can be transmitted by a node in a time slot = 3 The time required to transmit one frame = 1 Second Explain how TDMA protocol works to complete this task? How much time will it take to transmit all frames?

Answer 1

Answer:

Following are the description of the given nodes:

Explanation:

The Multiple Access frequency - division facilitates control by granting every node a fixed time slot. Also, every slot seems to be identical in width. Its whole channel bandwidth is often used in every channel node. Compared to FDMA it takes more time.  

Time slot=3 frames for all the above scenario

• In the first point, It is reserved the node 1, and as well as 3 frames were also transmitted 1.  
• In the second point, It is reserved the node 2, and as well as 3 frames are transmitted.
• In the third point, It is reserved 3 nodes, and as well as 3 frames were transmitted.  
• In the fourth point, It is reserved 4 slots and the transmit 3 frames.  
• In the fifth point, It stores the slot 1 and the transmit 3 frames.  
• In the sixth point, It stores the slot 2 and the transmit 1 frame.  
• In the seventh point, It stores the slot 3  and the transmit 3 frames.  
• In the Eight points, It stores the slot 3 and the transmit 2 frames.  

Time interval = number of frames in first slot Time to send 1 frame number of images  

                      $= 8 \times 3 \times 1 \\\\ = 8 \times 3 \\\\= 24 \ seconds$