The fourth one But I think
The answer to this is True. The government controls major aspects of economic production.
The dimensions of the smaller holding pens from the parameters given are; 96 ft and 31 ft
<h3>What dimensions will maximize the area?</h3>
From the complete question, if the side lengths of the big rectangle are x and y, then the expression for the area A is:
A = x*y
Then perimeter since we have 384 ft of fencing available is;
2x + 2y = 384
y = (384 - 2x)/2
y = 192 - x
Put 192 - x for y in area formula;
A = x(192 - x)
A = 192x - x²
Completing the square of this are equation gives;
A = 9216 - (x - 96)²
This means that A is maximum at x - 96 = 0
Thus, A is maximum when x = 96 ft
At A_max; y = 192 - 96 = 96 ft
Since the area of the bigger rectangle has been maximized, it means that we have also maximized the area of the smaller pens. Therefore its' dimensions will be;
x_small = 96 ft/3 = 31 ft
y_small = 96 ft
Read more about maximizing area at; brainly.com/question/9819619
Answer:
Volume = 480 cubic inches
Explanation:
We have the following relationships to work with
width w = h -3
length l = h + 4
area of base of prism a = l x w = 60 (1)
area of base in terms of h = (h-3)(h+4) =h² -3h + 4h -12 (2)
Setting (1) = (2) gives
h² + h -12 =60
h² + h -72 = 0
Factoring the LHS we get
(h+9)(h-8) = 0
The solutions for h are
h + 9 = 0 ==> h = -9
h - 8 = 0 ==> h = 8
Since h cannot be negative, h = 8 inches
Volume = base area x h = 60 x 8 = 480 cubic inches
<u>Note</u>
We do not have to calculate length and width separately, but if so,
w = 8 -3 = 5
l = 8 + 4 = 12
Thanks for telling. i would totally get caught off guard if the staff are mostly robots- robots scare me for whatever reason. probably because i have a feeling they might turn on us humans and destroy the world or something along those lines.
