Each "contour" is a pair of parallel lines with slope 8.
4p2-p=0 how do you solve this
1 answer:
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Answer:
The equation of line with slope and points ( - 1 , 3 ) is y =
x +
Step-by-step explanation:
Given equation of a line as :
y = x + 3
The line equation is in the form of y = m x + c
Where m is the slope of the line
Now while comparing given line equation with standard line equation ,
So , slope of the line m =
∵ Another line is passing through points ( - 1 , 3 ) , and is parallel to given line
Now <u>if two lines are parallel then slope of both lines are equal </u>
Let The slope of another line = M
So, M = m =
∴ The equation of line with slope and passing through points ( - 1 , 3 ) is
y - = M × ( x -
)
Or, y - 3 = × ( x + 1 )
or, 4 × ( y - 3 ) = 5 × ( x + 1 )
Or, 4 y - 12 = 5 x + 5
Or, 4 y = 5 x + 17
∴ y = x +
Hence The equation of line with slope and points ( - 1 , 3 ) is y =
x +
Answer