Question

You are holding a kite string in your hand. The angle of elevation from your hand to the kite is 44∘ and the distance to the kite is 250 feet. Your hand is 5 feet above the ground. How high is the kite? Round your answer to the nearest tenth of a foot.

Answer 1

Answer:

The height of the kite is equal to $178.7\ ft$

Step-by-step explanation:

see the attached figure to better understand the problem

The point A is your hand and point C is the kite

we know that

In the right triangle BCD

$sin(44^o)=\frac{CD}{BC}$ ---> by SOH (opposite side divided by the hypotenuse)

substitute the given values

$sin(44^o)=\frac{CD}{250}$

solve for CD

$CD=sin(44^o)(250)=173.7\ ft$

The height of the kite is equal to

$AB+CD=5+173.7=178.7\ ft$