The intersection of lines y=-14x+3 and y=-32x+3 is (0, 3)
<h3>How to determine the intersection of the lines?</h3>
The lines are given as:
y = -14x + 3 and y = -32x+3
Substitute y = -32x+3 in
-32x+3 = -14x + 3
Evaluate the like terms
-18x = 0
Divide by -18
x = 0
Substitute x = 0 in y = -14x + 3
y = -14(0) + 3
Evaluate
y = 3
Hence, the intersection of lines y=-14x+3 and y=-32x+3 is (0, 3)
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The answer is 301000070409
Answer: Integer
Step-by-step explanation: The answer would be integer
Answer:
625 metres
Step-by-step explanation:
Given the area function expressed as a(w)=-(w-25)^2+625.
The maximum area occurs at when da/dw = 0
da/dw = -2(w-25)
0 = -2(w-25)
-2(w-25) = 0
w - 25 = 0
w = 25
Substitute w = 25 into the modeled equation;
Recall a(w)=-(w-25)^2+625.
a(25)=-(25-25)^2+625
a(25) = 0+625
a(25) = 625
Hence the maximum area possible is 625 metres
