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Molodets [167]
3 years ago
10

If an mRNA is AUGCACUACUUG, write the complementary anti-codon tRNA nucleotide sequence

Biology
1 answer:
gayaneshka [121]3 years ago
3 0

Answer:

UACGUGAUGAAC

Explanation:

Translation is the second process of gene expression which occurs in the ribosome (organnelle for protein synthesis). It involves the synthesis of amino acid sequence using mRNA template. In the ribosome, the mRNA sequence (produced during transcription) is read in a group of three nucleotides called CODON. Each codon specifies a particular amino acid.

The reading of the mRNA is carried out by a special type of RNA molecule called transfer RNA (tRNA). tRNA reads the mRNA sequence using its ANTICODON (a group of three nucleotides complementary to the mRNA codon). The actual reading is done using complementary base pairing rule i.e. A-U, G-C.

The tRNA also carries the amino acid that corresponds the mRNA codon it reads.

Hence, in a case of an mRNA sequence: AUG CAC UAC UUG, the anticodon nucleotide sequence of the tRNA will read UAC GUG AUG AAC.

Note, this was done following the complementary base pairing rule (A-U, G-C).

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<h3>What are monosaccharides?</h3>

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When two monosaccharides are linked together by glycosidic bonds to form a single compound, the compound formed is called a disaccharide.

Considering the give question:

Suppose a 0.1M solution of a monosaccharide contains 1000 monosaccharide molecules. How many monosaccharide molecules would be in a 0.1 M solution of a disaccharide.

The number of monosaccharides molecules present in the 0.1 M solution of a disaccharide is determined as follows:

1 disaccharide molecule contains 2 monosaccharide molecules

0.1M solution of a monosaccharide contains 1000 monosaccharide molecules.

0.1 M solution of a disaccharide will contain 2 * 1000 monosaccharide molecules

0.1 M solution of a disaccharide will contain = 2000 monosaccharide molecules.

Learn more about monosaccharides and disaccharides at: brainly.com/question/731310

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