Here you go hope it helps
<span> f(3) = f(2) + f(1) => 3 + 2 = 5
f(4) = f(3) + f(2) => 5 + 3 = 8
f(5) = f(4) + f(3) => 8 + 5 = 13
Therefore the sequence is 2, 3, 5, 8, 13,.....a Fibonacci sequence.
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Consider the number of the adult tickets is x
X+2x=276
3x=276
X=92
So the student tickets is =184
Answer:
- as written, c ≈ 0.000979 or c = 4
- alternate interpretation: c = 0
Step-by-step explanation:
<em>As written</em>, you have an equation that cannot be solved algebraically.
(32^2)c = 8^c
1024c = 8^c
1024c -8^c = 0 . . . . . . rewrite as an expression compared to zero
A graphical solution shows two values for c: {0.000978551672551, 4}. We presume you're interested in c = 4.
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If you mean ...
32^(2c) = 8^c
(2^5)^(2c) = (2^3)^c . . . . rewriting as powers of 2
2^(10c) = 2^(3c) . . . . . . . simplify
10c = 3c . . . . . . . . . . . . . .log base 2
7c = 0 . . . . . . . . . . . . . . . subtract 3c
c = 0 . . . . . . . . . . . . . . . . divide by 7