Got answer wrong can u guys tell me what's the answer and why??
2 answers:
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Answer:
- -108.26
- -108.13
- -108.052
- -108.026
- -108
Step-by-step explanation:
A graphing calculator or spreadsheet is useful for making the repeated function evaluations required.
The average velocity on the interval [a,b] will be ...
v avg = (y(b) - y(a))/(b-a)
Here, all the intervals start at a=3, so the average velocity for the given values of t will be ...
v avg = (y(3+t) -y(3))/((3+t) -3) = (y(3+t) -y(3))/t
This can be computed for each of the t-values given. The results are shown in the attached table.
__
We note that the fractional part of the velocity gets smaller in proportion to t getting smaller. We expect it to go to 0 when t goes to 0.
The estimated instantaneous velocity is -108 ft/s.
_____
We can simplify the average velocity equation to ...
v avg = ((48(3+t) -26(t+3)^2) -(48(t+3) -26(3)^2)) / t
= (48t -26(t^2 +6t))/t
= 48 -26t -156
<em> v avg = -108 -26t</em>
Then the average velocity at t=0 is -108.
The corrected parts of the question has been attached to this answer.
Answer:
A) Probability that the error is less than 0.2 mm; P(X < 0.2) = 0.0272
B) Mean Error (E(X)) = 0.6
C) Variance Error (V(X)) = 0.04
D) Answer properly written in attachment (Page 2)
E) P(0<X<0.8) = 0.8192
Step-by-step explanation:
The probability density function of X is;
f(x) = { 12(x^(2) −x^(3) ; 0<x<1
So, due to the integral symbol and for clarity sake, i have attached all the explanations for answers A - D.
E) The probability that the specification for the error to be between 0 to 0.8 mm is met will be;
P(0<X<0.8) = F(0.8) − F(0) =12([(0.8)^(3)] /3] −[(0.8)^(4)]/4]
= 0.8192
So, the probability is 0.8192.
