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Aleonysh [2.5K]
3 years ago
5

I need help asap, please

Mathematics
2 answers:
Hunter-Best [27]3 years ago
6 0

Answer:

yous math symblom

Step-by-step explanation:

its a good website for that

OverLord2011 [107]3 years ago
6 0

Answer:

x = -6

Step-by-step explanation:

4(x-6)+4=6x-8

Multiply by four in parenthesis.

4x-20=6x-8

Add 20 on both sides.

4x=6x+12

Subtract 6.

-2x=12

Divide -2

z = -6

:)

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Did you mean mongol?
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3 years ago
How does the graph of g(x)=⌈x⌉+7 differ from the graph of f(x)=⌈x⌉?
Lorico [155]
The addition of +7 influences the y values of the graph. Since it is positive, the graph of y=IxI would be moved 7 units upwards. 

Hope I helped :)
8 0
3 years ago
Is the following function an even function, odd function, or neither?
expeople1 [14]

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Step-by-step explanation:

3 0
4 years ago
Find the perimeter of the quarter-circle. Give your answer to the nearest whole number.
Bezzdna [24]

Answer:

The perimeter of the quarter-circle is 200 cm.

Step-by-step explanation:

Given that the angle of quarter-circle is 90°. So using Length of Arc formula, you are able to find the length of curve :

arc =  \frac{θ}{360}  \times 2 \: \pi \: r

Let r be radius = 56 cm,

Let θ = 90°

arc =  \frac{90}{360}  \times 2 \times\pi \times 56

=  \frac{1}{4}  \times 2 \times \pi \times 56

=  \frac{1}{2}  \times \pi \times 56

= 28\pi \: cm

We have already found the arc. Next we have to add up together to find the perimeter :

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6 0
3 years ago
Read 2 more answers
Is the line through points P(0, –9) and Q(2, –8) perpendicular to the line through points R(1, 4) and S(3, 3)? Explain
Serjik [45]
The quickest way to tell if a line is perpendicular is to find the slope, so you'll need to get the slope for both lines

PQ = ((-8) - (-9))/(2 - 0) = 1/2

and, for reference, a perpendicular slope is the negative reciprocal of the original (so we're looking for -2)

RS = (3 - 4)/(3 - 1) = -1/2

so, no, these two lines aren't perpendicular because the slope of RS is only the negative of PQ, not the negative <em>reciprocal</em>.
3 0
3 years ago
Read 2 more answers
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