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There are different kinds of trade. Trading in foreign currency options would most likely be an appropriate hedging tool for individual investors who want to hedge the risk on specific U.S. exchange-listed stocks.
<h3>Currency option hedges</h3>
- Currency option hedges are known to be tools that are used in international business.
An example, when an American importer is said to agree to buy some food equipment from a Chinese manufacturer at a later future date. The transaction will be carried out in Chinese currency.
The American importer has therefore made an hedge by buing currency options on the Chinese currency.
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Answer:
3.8 times
Explanation:
Inventory turnover indicates how many times a company sells and replaces its stock of goods during a particular period. The formula for inventory turnover ratio is the cost of goods sold divided by the average inventory for the same period.
$ 320,000 / 63,000 = 5.1 times in 2022
$283,500 / 32,000 = 8.9 times in 2023
Therefore inventory turnover increase as a result of the switch to the JIT system by 8.9 times - 5.1 times = 3.8 times
Answer:
The correct answer is lower-class nonwhite.
Explanation:
The lower class is the poorest population segment of human society. It is characterized by having great gaps in its way of life and limitations in terms of access to economic resources. They are usually unemployed people, who do not own their own home or other goods or properties that are essential for living.
To this socioeconomic class belong people with very low educational levels, barely with primary education and some with secondary education. Some casual or independent workers also enter this class. Lower class families do not have good basic services in their homes.
<span>n/2 = average number of items to search.
Or more precisely (n+1)/2
I could just assert that the answer is n/2, but instead I'll prove it. Since each item has the same probability of being searched for, I'll simulate performing n searches on a list of n items and then calculate the average length of the searches. So I'll have 1 search with a length of 1, another search looks at 2, next search is 3, and so forth and so on until I have the nth search looking at n items. The total number of items looked at for those n searches will be:
1 + 2 + 3 + 4 + ... + n
Now if you want to find the sum of numbers from 1 to n, the formula turns out to be n(n+1)/2
And of course, the average will be that sum divided by n. So we have (n(n+1)/2)/n = (n+1)/2 = n/2 + 1/2
Most people will ignore that constant figure of 1/2 and simply say that if you're doing a linear search of an unsorted list, on average, you'll have to look at half of the list.</span>