The number of microorganisms that I will have after 10 days would be: 245.41 microoganisms.
<h3>How to calculate the number of microorganisms that I will have after 10 days?</h3>
To calculate the number of microorganisms that I will have after 10 days, I must perform the following operations:
We need to find 37% of 55 as shown below:
- 55 ÷ 100 = 0.55
- 0.55 x 37% = 20.35
- 55 + 20.35 = 75.35
So after 2 days I will have 75.35 microorganisms.
- 75.35 ÷ 100 = 0.75
- 0.7535 x 37% = 27.87
- 75.35 + 27.87 = 103.22
On the fourth day I will have: 103.22 microorganisms.
- 103.22 ÷ 100 = 1.0322
- 1.0322 x 37% = 38.19
- 103.22 + 38.19 = 141.41
On the sixth day I will have 141.41 microorganisms.
- 141.41 ÷ 100 = 1.4141
- 1.4141 x 37% = 52.32
- 141.41 + 52.32 = 193,73
On the eighth day I will have 193.73 microorganisms.
- 193.73 ÷ 100 = 1.9373
- 1.9373 x 37% = 71.68
- 193.73 + 71.68 = 265.41
On the tenth day I will have 245.41 microoganisms.
Learn more about percentages in: brainly.com/question/13450942
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Answer:
um 145 lbs
Step-by-step explanation: basic math bruv
The answer is £316.80.
This is because you're working out the original price from a percentage increase.
To do this, you do the original price ÷ (1- percentage increase as a decimal).
So it would be 352 ÷ (1 - 0.10) which is 352 ÷ 0.9.
And that equals to £316.80.
Answer:
X=5
Step-by-step explanation:
plz mark as brainliest
recall your d = rt, distance = rate * time.
j = jet's rate
w = wind's rate
so with the wind the actual speed of the Jet is really j + w, because the wind is adding speed to it, and against it is j - w, since the wind is eroding speed from it.
![\bf \begin{array}{lcccl} &\stackrel{miles}{distance}&\stackrel{mph}{rate}&\stackrel{hours}{time}\\ \cline{2-4}&\\ \textit{against the wind}&8730&j-w&9\\ \textit{with the wind}&7260&j+w&6 \end{array}~\hfill \begin{cases} 8730=(j-w)(9)\\ 7260=(j+w)(6) \end{cases} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{using the 1st equation}}{\cfrac{8730}{9}=j-w\implies }970=j-w\implies 970+w=j \\\\[-0.35em] ~\dotfill](https://tex.z-dn.net/?f=%5Cbf%20%5Cbegin%7Barray%7D%7Blcccl%7D%20%26%5Cstackrel%7Bmiles%7D%7Bdistance%7D%26%5Cstackrel%7Bmph%7D%7Brate%7D%26%5Cstackrel%7Bhours%7D%7Btime%7D%5C%5C%20%5Ccline%7B2-4%7D%26%5C%5C%20%5Ctextit%7Bagainst%20the%20wind%7D%268730%26j-w%269%5C%5C%20%5Ctextit%7Bwith%20the%20wind%7D%267260%26j%2Bw%266%20%5Cend%7Barray%7D~%5Chfill%20%5Cbegin%7Bcases%7D%208730%3D%28j-w%29%289%29%5C%5C%207260%3D%28j%2Bw%29%286%29%20%5Cend%7Bcases%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7Busing%20the%201st%20equation%7D%7D%7B%5Ccfrac%7B8730%7D%7B9%7D%3Dj-w%5Cimplies%20%7D970%3Dj-w%5Cimplies%20970%2Bw%3Dj%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill)
![\bf \stackrel{\textit{using the 2nd equation}}{\cfrac{7260}{6}=j+w}\implies 1210=j+w\implies \stackrel{\textit{doing some substitution on \underline{j}}}{1210=(970+w)+w} \\\\\\ 1210=970+2w\implies 240=2w\implies \cfrac{240}{2}=w\implies \boxed{120=w} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{we know that}}{970+w=j}\implies 970+120=j\implies \boxed{1090=j}](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7B%5Ctextit%7Busing%20the%202nd%20equation%7D%7D%7B%5Ccfrac%7B7260%7D%7B6%7D%3Dj%2Bw%7D%5Cimplies%201210%3Dj%2Bw%5Cimplies%20%5Cstackrel%7B%5Ctextit%7Bdoing%20some%20substitution%20on%20%5Cunderline%7Bj%7D%7D%7D%7B1210%3D%28970%2Bw%29%2Bw%7D%20%5C%5C%5C%5C%5C%5C%201210%3D970%2B2w%5Cimplies%20240%3D2w%5Cimplies%20%5Ccfrac%7B240%7D%7B2%7D%3Dw%5Cimplies%20%5Cboxed%7B120%3Dw%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7Bwe%20know%20that%7D%7D%7B970%2Bw%3Dj%7D%5Cimplies%20970%2B120%3Dj%5Cimplies%20%5Cboxed%7B1090%3Dj%7D)
