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bonufazy [111]
3 years ago
12

2. How much heat is needed to warm .052 kg of gold from 30°C to 120°C

Mathematics
1 answer:
Doss [256]3 years ago
7 0

Answer: 90 degrees Celsius

Step-by-step explanation:

120-30 = 90

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Question 5 (2 points)
ollegr [7]

Answer:

c cuh

Step-by-step explanation:

(idk the answer)

4 0
3 years ago
Simplify: log81/8 + 2log2/3 - 3log 3/2 +log 3/4​
MissTica

Answer:

0.

Step-by-step explanation:

Using the laws of logarithms:

log81/8 + 2log2/3 - 3log 3/2 + log 3/4​

= log 81/8 + log (2/3)^2 - log (3/2)^3 + log 3/4

= log 81/8 + log 4/9 - log 27/8 + log 3/4

= log 81/8 + log 4/9 - (log 27/8 - log 3/4)

= log (81/8 *  4/9) - log (27/8 * 4/3)

= log 9/2 - log 9/2

= 0.

5 0
3 years ago
Garrett ran 3 1/4 miles on Monday. on Wednesday he ran 2 2/3 miles father than on Monday. on Friday he ran the same distance as
vlabodo [156]
3 1/4 + 2 2/3

3 1/4= 13/4
2 2/3= 8/3

13/4+8/3= 5 11/12

6 0
3 years ago
Help and show work that will make my day ❤️
kolezko [41]
H equals 30 because 3 times 6 is 18 so 5 times 6 is 30
7 0
3 years ago
M(-3,2) is the midpoint of AP. If A has coordinates (-1,5), what are the<br> coordinates of P?
Inessa05 [86]

Answer:

<h3>            P(-5, -1)</h3>

Step-by-step explanation:

If M is midpoint of AP then:  

x_P-x_M=x_M-x_A\qquad\quad\ \wedge\qquad y_P-y_M=y_M-y_A\\\\x_P-(-3)=-3-(-1)\qquad\wedge\qquad y_P-2=2-5\\\\x_P+3=-3+1\qquad\quad\ \wedge\qquad\quad y_P-2=-3\\\\x_P=-3+1-3\qquad\quad\ \wedge\qquad\quad y_P=-3+2\\\\x_P=-5\qquad\qquad\ \wedge\qquad\qquad y_P=-1

8 0
3 years ago
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