All categories

3 years ago

Which of the following best shows how the internet affects the economic

Mathematics

1 answer:

weqwewe [10]3 years ago

6 0

Answer:The answer is B. I just did it. good luck!

Step-by-step explanation:

You might be interested in

What is 28.26 rounded to the nearest hundreth

In-s [12.5K]

28.26 rounded to the nearest hundredth is 28.3

5 0

3 years ago

Write an equation for: the sum of three times 'y' and 11 is 32

nadya68 [22]

Hey!!

Question: The sum of three times 'y' and 11 is 32

Answer: 3y+11=32

Hope it helps

Good luck on your assignment

8 0

3 years ago

Read 2 more answers

7. By using binomial expansion show that the value of (1.01)^12 exceed the value of (1.02)^6 by 0.0007 correct to four decimal p

BlackZzzverrR [31]

Binomial expansion is used to factor expressions that can be expressed as the power of the sum of two numbers.

The proof that (1.01)^12 exceeds (1.02)^6 by 0.0007 is $\mathbf{(1.01)^{12} - (1.02)^6 \approx 0.0007 }$

The expressions are given as:

$\mathbf{(1.01)^{12}\ and\ (1.02)^6}$

A binomial expression is represented as:

$\mathbf{(a + b)^n = \sum\limits^n_{k=0}^nC_k a^{n - k}b^k}$

Express 1.01 as 1 + 0.01

So, we have:

$\mathbf{(1.01)^{12} = (1 + 0.01)^{12}}$

Apply the above formula

$\mathbf{(1.01)^{12} = ^{12}C_0 \times 1^{12 - 0} \times 0.01^0 + ......... .......... + ^{12}C_{12} \times 1^{12 - 12} \times 0.01^{12} }}$

$\mathbf{(1.01)^{12} = 1 \times 1 \times 1 + ......... .......... + 1 \times 1 \times 10^{-24} }}$

$\mathbf{(1.01)^{12} = 1 + ......... .......... + 10^{-24} }}$

This gives

$\mathbf{(1.01)^{12} = 1.1268\ (approximated)}$

Similarly,

Express 1.02 as 1 + 0.02

So, we have:

$\mathbf{(1.02)^6 = (1 + 0.02)^6}$

Apply $\mathbf{(a + b)^n = \sum\limits^n_{k=0}^nC_k a^{n - k}b^k}$

$\mathbf{(1.02)^6 = ^6C_0 \times 1^{6 - 0} \times 0.02^0 + ^6C_1 \times 1^{6 - 1} \times 0.02^1 +.............. + ^6C_6 \times 1^{6 - 6} \times 0.02^6 }$ $\mathbf{(1.02)^6 = 1 \times 1 \times 1 + 6 \times 1 \times 0.02 +.............. + 1 \times 1 \times 6.4 \times 10^{-11} }$

$\mathbf{(1.02)^6 = 1 + 0.12 +.............. + 6.4 \times 10^{-11} }$

This gives

$\mathbf{(1.02)^6 = 1.1261\ (approximated) }$

Calculate the difference as follows:

$\mathbf{(1.01)^{12} - (1.02)^6 \approx 1.1268 - 1.1261 }$

$\mathbf{(1.01)^{12} - (1.02)^6 \approx 0.0007 }$

The above equation means that:

(1.01)^12 exceed the value of (1.02)^6 by 0.0007

Read more about binomial expansions at:

brainly.com/question/9554282

7 0

3 years ago

Answer both questions for seventeen points and i’ll name you brainliest!! Type the correct answer in each box. Use numerals inst

Elden [556K]

$\bf -2(bx-5)=16\implies bx-5=\cfrac{16}{-2}\implies bx-5=-8\implies bx=-8+5 \\\\\\ bx=-3\implies \boxed{x=\cfrac{-3}{b}} \\\\[-0.35em] ~\dotfill\\\\ b=3\qquad \qquad x=\cfrac{-3}{\underset{b}{3}}\implies \boxed{b=-1}$

4 0

3 years ago

Decimal Place Value write the word form and decimal for each shaded part.

Solnce55 [7]

The answer is Four tenths

3 0

4 years ago

Read 2 more answers