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Paladinen [302]

3 years ago

7

Please solve!!!!!!!!

1 answer:

Naily [24]3 years ago

7 0

Answer:

<h2>hope it helps you see the attachment for further information .......</h2>

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Solve pls branliest.

galina1969 [7]

Answer:

1. no. 2. yes. 3. no. 4. yes. 5. yes.

Step-by-step explanation:i'll explain how to identify integers.

The integers are ..., -4, -3, -2, -1, 0, 1, 2, 3, 4, ... -- all the whole numbers and their opposites (the positive whole numbers, the negative whole numbers, and zero). Fractions and decimals are not integers. For example, -5 is an integer but not a whole number or a natural number. ... Integers are numbers that do not have a fractional part, including positive and negative numbers and zero. Whole numbers are positive integers and zero. Natural numbers are positive integers and are sometimes called counting numbers. tell me if you need me to explain more.

7 0

3 years ago

True or false: to obtain the graph of f(x)=square root x+2 shift the graph of y=square root X horizontally to the right 2 units.

Whitepunk [10]

Answer:

true

Step-by-step explanation:

3 0

3 years ago

Given: BD = BF DE ⊥ BC , FK ⊥ AB Prove: ED ≅ FK

sergeinik [125]

This is the picture I am not very good at proofs but hopefully someone can solve it.

8 0

3 years ago

Read 2 more answers

Can someone help me with this question please

rusak2 [61]

The correct answer is c

6 0

3 years ago

Researchers examined the bill color (in hue degree) of male and female zebra finches. Here are the summary statistics from the s

sesenic [268]

Answer:

The answer to this question can be defined as follows:

Step-by-step explanation:

In the question some iformation is missing, which can be defined as follows:

Given:

The value of males:

$n_1= 59\\s_1= 1.46\\\bar y_1=2.91\\$

The value of Females:

$n_2=60\\s_2= 2.48\\\bar y_2=7.42\\$

Calculating Degrees of Freedom:

$\bold{ df=\frac{\frac{s_1^2}{n_1}+\frac{s_2^2}{n_2}}{ \frac{1}{n_1-1} (\frac{s_1^2}{n_1})^2+\frac{1}{n_2-1} (\frac{s_2^2}{n_2})^2}}\\\\\\$

$=\frac{(\frac{1.46^2}{59}+\frac{2,48^2}{60})^2}{ \frac{1}{59-1} (\frac{1.46^2}{59})^2+\frac{1}{60-1} (\frac{2.48^2}{60})^2}\\$

$=9.58 or 95$

$\alpha= 1-0.95\\\\$

$= 0.05$

for 95% confidence interval are:

$\frac{\alpha}{2} = \frac{0.05}{2} = 0.025$

From its t-distribution table , the value of t has an region of ( $\frac{\alpha}{2} \ \ 0.025$ ) for (df=95) in its upper tail.

shall be given by = t {0.025}=1.985

Calculating the margin of Error:

$M_OE =t_{0.025} \times \sqrt{\frac{s_1^2}{n_1}+\frac{s_2^2}{n_2}}$

$=1.985\times \sqrt{\frac{1.46^2}{59}+\frac{2.48^2}{60}}\\\\=0.739$

The difference in mean bill color " $\mu_2 -\mu_1$ " with 95% confidence intervals:

$\to (7.42 - 2.91) \pm 0.739\\\\\to 4.51 \pm 0.739$

Lower limit=3.771

Upper limit = 5.249

6 0

3 years ago