3 years ago

Please solve!!!!!!!!

1 answer:

Naily [24]3 years ago

7 0

Answer:

<h2>hope it helps you see the attachment for further information .......</h2>

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soldier1979 [14.2K]

Answer:

Let y = f(x)

$= > y = \frac{19}{ {x}^{3} }$

$= > {x}^{3} = \frac{19}{y}$

$= > x = \sqrt[ 3]{ \frac{19}{y} }$

${f}^{ - 1} (x) = \frac{ \sqrt[3]{19} }{ \sqrt[3]{x} }$

<h2>option A</h2>

4 0

3 years ago

Jobisdone [24]

The terms are 3n, 4p, and 2.

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3 years ago

Nataly_w [17]

Hope this helps I got (-1, 7)

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3 years ago

Anuta_ua [19.1K]

Answer:

I think i wanna say one of the fractions

Step-by-step explanation:

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2 years ago

Softa [21]

Answer:

5,6241

Step-by-step explanation:

I have no idea if this is correct but I hope it is. I hope this helps.

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3 years ago

Please solve!!!!!!!!​