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miv72 [106K]
3 years ago
11

Can someone help me with this question please

Mathematics
1 answer:
rusak2 [61]3 years ago
6 0
The correct answer is c
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e≈2.7 1 8 2 8 182846.....


Fifth decimal place is bold 8.

When we round up to 5th decimal place, we get

e≈2.7 1 8 2 8.

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Solve the following automotive-services problems based on the examples shown previously. Choose the correct answer.
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The ratio of ducks to geese in a pond is 3 : 5. There are 27 ducks.<br> How many geese are there?
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After a college football team once again lost a game to their archrival, the alumni association conducted a survey to see if alu
valentina_108 [34]

Answer:

P-value for this hypothesis test is 0.00175.

Step-by-step explanation:

We are given that the alumni association conducted a survey to see if alumni were in favor of firing the coach.

A simple random sample of 100 alumni from the population of all living alumni was taken. Sixty-four of the alumni in the sample were in favor of firing the coach.

<u><em>Let p = proportion of all living alumni who favored firing the coach</em></u>

SO, Null Hypothesis, H_0 : p = 0.50   {means that the majority of alumni are not in favor of firing the coach}

Alternate Hypothesis, H_A : p > 0.50   {means that the majority of alumni are in favor of firing the coach}

The test statistics that will be used here is <u>One-sample z proportion</u> <u>statistics</u>;

                                  T.S.  = \frac{\hat p-p}{{\sqrt{\frac{\hat p(1-\hat p)}{n} } } } }  ~ N(0,1)

where, \hat p  = sample proportion of the alumni in the sample who were in favor of firing the coach = \frac{64}{100} = 0.64

            n = sample of alumni = 100

So, <em><u>test statistics</u></em>  =  \frac{0.64-0.50}{{\sqrt{\frac{0.64(1-0.64)}{100} } } } }

                               =  2.92

<u>Now, P-value of the hypothesis test is given by ;</u>

         P-value = P(Z > 2.92) = 1 - P(Z \leq 2.92)

                                             = 1 - 0.99825 = 0.00175

Therefore, the P-value for this hypothesis test is 0.00175.

4 0
4 years ago
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