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3 years ago

Proportions and Similarity

1 answer:

5 0

$\bf \cfrac{length}{width}\qquad \qquad \stackrel{A}{\cfrac{4}{5}}\qquad \stackrel{B}{\cfrac{20}{25}}\implies \cfrac{4}{5}\qquad \checkmark$

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I will do anything if you answer!!! There's a photo!!! PLEASE!!!

Makovka662 [10]

A, it's always true
remember commutative property
a+b=b+a
a and b can be negativ numbers

so equatinos
-5.2+7.71=2.51
7.71-5.2=2.51

-8.65+3.94=-4.62
3.94-8.65=-4.62

B.
-5.2-7.71=-12.91
7.71-(-5.2)=12.91

-8.65-3.94=-12.59
3.94-(-8.65)=12.59

always false

C. when you change the order, you are subtracting a different number from a different number than before

8 0

3 years ago

Six friends share 4 apples equally. How much apples does each friend friend get?

Zinaida [17]

Half and apple each

5 0

2 years ago

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Need help pls<br>thank you in advance

ira [324]

Answer:

<u />

$\textsf{Mean}\:\overline{X}=\sf \dfrac{\textsf{sum of all the data values}}{\textsf{total number of data values}}$

$\implies \sf Mean\:(Nilo)=\dfrac{5+6+14+15}{4}=\dfrac{40}{4}=10$

$\implies \sf Mean\:(Lisa)=\dfrac{8+9+11+12}{4}=\dfrac{40}{4}=10$

<h3><u>Standard Deviation</u></h3>

$\displaystyle \textsf{Standard Deviation }s=\sqrt{\dfrac{\sum X^2-\dfrac{(\sum X)^2}{n}}{n-1}}$

$\begin{aligned}\displaystyle \textsf{Standard Deviation (Nilo)} & =\sqrt{\dfrac{(5^2+6^2+14^2+15^2)-\dfrac{(5+6+14+15)^2}{4}}{4-1}}\\\\& = \sqrt{\dfrac{482-\dfrac{40^2}{4}}{3}}\\\\& = \sqrt{\dfrac{82}{3}}\\\\& = 5.23\end{aligned}$

$\begin{aligned}\displaystyle \textsf{Standard Deviation (Lisa)} & =\sqrt{\dfrac{(8^2+9^2+11^2+12^2)-\dfrac{(8+9+11+12)^2}{4}}{4-1}}\\\\& = \sqrt{\dfrac{410-\dfrac{40^2}{4}}{3}}\\\\& = \sqrt{\dfrac{10}{3}}\\\\& = 1.83\end{aligned}$

<h3><u>Summary</u></h3>

Nilo has a mean score of 10 and a standard deviation of 5.23.

Lisa has a mean score of 10 and a standard deviation of 1.83.

The <u>mean</u> scores are the <u>same</u>.

Nilo's standard deviation is higher than Lisa's. Therefore, Nilo's test scores are more <u>spread out</u> that Lisa's, which means Lisa's test scores are more <u>consistent</u>.

5 0

2 years ago

a person made 4 blankets each blanket used 180 inches of ribbon for the border how many yards of ribbon did the person use for a

adell [148]

Answer:

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Suppose the true proportion of voters in the county who support a restaurant tax is 0.5. Consider the sampling distribution for

Ahat [919]

Answer:

the mean of the sampling distribution for the proportion of supporters with sample size n = 165 is 0.5.

Step-by-step explanation:

According to the Central Limit Theorem, assuming the sampling is random and sample size is big enough (≥30) the mean of the sampling distribution is the population mean.

Therefore the mean of the sampling distribution for the proportion of supporters with sample size n = 165 is 0.5

4 0

3 years ago